Grep一个字，并从日志文件找到它的Count不同的时间 [英] Grep a word and find its Count from log file for different times

问题描述

包含以下数据的日志文件。

log file which contains following data.

2014-10-19 17:30:25:
Creating destination directory: "\master1\users\jamesk\Java\chapter05\tech-support-complete\doc\" 
Loading source file Error \\master1\users\jamesk\Java\chapter05\tech-support-complete\JamesKohout.java... 
onstructing Javadoc information...Error
31 Error Standard Doclet version 1.6.0_26 Error
-encoding Error
19 windows-1252 
20 -charset Error
21 windows-1252 
22 -docletpath 
2014-10-19 18:30:25:
Creating destination directory: "\master1\users\jamesk\Java\chapter05\tech-support-complete\doc\" 
Loading source file Error \\master1\users\jamesk\Java\chapter05\tech-support-complete\JamesKohout.java... 
onstructing Javadoc Error information...
31 Standard Doclet version 1.6.0_26 Error
-encoding Error
19 windows-1252 
20 -charset Error
21 windows-1252 
22 -docletpath 
2014-10-19 19:30:25:
Creating destination directory: "\master1\users\jamesk\Java\chapter05\tech-support-complete\doc\" 
Loading source file Error \\master1\users\jamesk\Java\chapter05\tech-support-complete\JamesKohout.java... 
onstructing Javadoc information...Error
31 Standard Doclet version 1.6.0_26 Error
-encoding 
19 windows-1252 
20 -charset Error
21 windows-1252 
22 -docletpath 
2014-10-19 20:30:25:
Creating destination directory:Error "\master1\users\jamesk\Java\chapter05\tech-support-complete\doc\" 
Loading source file Error \\master1\users\jamesk\Java\chapter05\tech-support-complete\JamesKohout.java... 
onstructing Javadoc information...
31 Standard Doclet version 1.6.0_26 Error
-encoding Error
19 windows-1252 
20 -charset Error
21 windows-1252 Error
22 Error -docletpath

我想在Unix / python中编写一个脚本，它会覆盖单词Error，并从上面的日志文件中找到它的wordcount在不同的时间。
该文件包含不同时间值的数据。字Error在第一个时间间隔有一个计数6，第二个时间间隔的计数为5，以此类推。
我想输出为

I want to write a script in Unix/python which greps the word "Error" and finds the wordcount of it from above log file at different times. The file contains Data of Different time intevals.The word Error has a count 6 at the first time interval,the count at second time interval is 5 and so on. I want the output as

2014-10-19 17:30:25:     Error Count=6
2014-10-19 18:30:25:     Error Count=5
2014-10-19 19:30:25:     Error Count=4
2014-10-19 20:30:25:     Error Count=7

我尝试使用以下命令但它只给出总字数整个文件。

I tried with the following command But it only gives the total word count present in the whole file.

grep -i "Error" | wc -l

请帮助。
谢谢。

Please Help. Thanks.

推荐答案

import re
pattern=re.compile(r"\d{4}-\d{1,2}-\d{1,2}\s+\d{1,2}:\d{1,2}:\d{1,2}:|Error",re.IGNORECASE)
ll=pattern.findall(x)
d={}
for x in ll:
    if x!="Error":
        d[x]=0
        last=x
    else:
        d[last]=d[last]+1
print d

这里x是您的数据或file.read（）。

Here x is your data or file.read().

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