如何使用cron作业运行python文件 [英] How to run a python file using cron jobs

问题描述

您已经创建了一个python文件，例如 file_example.py

Hi I have created a python file for example as file_example.py

文件将输出sensex

The file will output the sensex value

假设linux系统上的文件路径为 /Desktop/downloads/file_example.py

Suppose the path of the file on linux system is /Desktop/downloads/file_example.py

我通常会运行 python file_example.py

但我想设置一个cron工作，每2分钟运行python文件，位于上面的路径

But I want to set a cron job to run the python file every 2 min which is located at the above path

任何人都可以让我知道如何做

Can anyone please let me know how to do this

已修改的代码：

我已编辑代码并创建了一个bash脚本

I had edited the code and created a bash script with the name test.sh as indicated below

#!/bin/bash 
cd /Desktop/downloads/file_example.py
python file_example.py 2>log.txt 

当我运行上述文件，将显示以下错误：

When I run the above file, the following error is displayed:

sh-4.2$ python test.sh
  File "test.sh", line 3
    python test.py 2>log.txt 
              ^
SyntaxError: invalid syntax

推荐答案

假设您使用的是unix操作系统，您可以执行以下操作。

Assuming you are using a unix OS, you would do the following.

编辑crontab文件使用命令

edit the crontab file using the command

crontab -e

添加类似下面的行

*/2 * * * * /Desktop/downloads/file_example.py

这可以用来运行其他脚本，只需使用脚本的路径需要

this can be used to run other scripts simply use the path to the script needed i.e.

*/2 * * * * /path/to/script/to/run.sh

时间的解释如下（在数字之前添加一个星号和斜杠以运行每n个时间步，分钟）

An explanation of the timing is below (add a star and slash before number to run every n timesteps, in this case every 2 minutes)

* * * * * command to be executed
- - - - -
| | | | |
| | | | ----- Day of week (0 - 7) (Sunday=0 or 7)
| | | ------- Month (1 - 12)
| | --------- Day of month (1 - 31)
| ----------- Hour (0 - 23)
------------- Minute (0 - 59)

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