使用反引号的Cron错误 [英] Cron error with using backquotes
问题描述
以下命令行工作正常
/usr/bin/mysqldump -uUser -pPass Db_name > /var/www/db_backup/db.`date +%Y%m%d%H%M`.sql
但是当我尝试在cron中这样做时,会出现错误:
but when I try to do that in cron, I get the error:
bad ` sign
errors in crontab file, can't install
我看到网上的其他人解决了同样的问题逃避百分号,但这没有帮助,我尝试它只是日期内的反引号没有格式说明符,仍然有错误。
I saw someone else on the net solve the same problem by escaping the percent signs, but that didn't help and I tried it with just date inside backquotes with no format specifiers and still got the errors.
我也看过
授予我可以把它放到一个脚本并执行,我想 - 但有什么乐趣是吗?
Granted I could just throw it into a script and execute that I suppose - but what fun is that?
任何想法?我使用的是RHEL 5。
Any ideas? I'm using RHEL 5.
推荐答案
使用 $()
而不是反引号。你可能需要转义百分号,因为 cron
将它们转换为换行符。
Try it with $()
instead of backticks. And you probably do need to escape the percent signs since cron
converts them to newlines otherwise.
* 0 * * * /usr/bin/mysqldump -uUser -pPass Db_name > /var/www/db_backup/db.$(date +\%Y\%m\%d\%H\%M).sql
此外,您应该将密码存储在具有安全权限(例如600或640)的选项文件中,而不是在命令行上传递。
Also, you should store the password in an option file with secure permissions (eg. 600 or 640) instead of passing it on the command line.
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