PHP错误在cronjob，工作正常提示 [英] PHP Errors on a cronjob, works fine at prompt

问题描述

我在cronjob上运行以下脚本...

I am running the following script on a cronjob...

cd /etc/parselog/
php run_all.php >/dev/null

，并得到以下错误：

[05-May-2009 20:30:12] PHP Warning:  PHP Startup: Unable to load dynamic library './pdo.so' - ./pdo.so: cannot open shared object file: No such file or directory in Unknown on line 0
[05-May-2009 20:30:12] PHP Warning:  PHP Startup: Unable to load dynamic library './mysql.so' - ./mysql.so: cannot open shared object file: No such file or directory in Unknown on line 0
[05-May-2009 20:30:12] PHP Warning:  PHP Startup: Unable to load dynamic library './mysql.so' - ./mysql.so: cannot open shared object file: No such file or directory in Unknown on line 0
[05-May-2009 20:30:12] PHP Warning:  PHP Startup: Unable to load dynamic library './mysqli.so' - ./mysqli.so: cannot open shared object file: No such file or directory in Unknown on line 0
[05-May-2009 20:30:12] PHP Warning:  PHP Startup: Unable to load dynamic library './odbc.so' - ./odbc.so: cannot open shared object file: No such file or directory in Unknown on line 0
[05-May-2009 20:30:12] PHP Warning:  PHP Startup: Unable to load dynamic library './pdo.so' - ./pdo.so: cannot open shared object file: No such file or directory in Unknown on line 0
[05-May-2009 20:30:12] PHP Warning:  PHP Startup: Unable to load dynamic library './pdo_mysql.so' - ./pdo_mysql.so: cannot open shared object file: No such file or directory in Unknown on line 0
[05-May-2009 20:30:12] PHP Warning:  PHP Startup: Unable to load dynamic library './pdo_odbc.so' - ./pdo_odbc.so: cannot open shared object file: No such file or directory in Unknown on line 0
[05-May-2009 20:30:12] PHP Warning:  PHP Startup: Unable to load dynamic library './pdo_sqlite.so' - ./pdo_sqlite.so: cannot open shared object file: No such file or directory in Unknown on line 0
[05-May-2009 20:30:12] PHP Fatal error:  Call to undefined function mysql_connect() in /etc/parselog/stats_downloads.php on line 5

这是我的$ PATH字符串在提示符：

This is my $PATH string at the prompt:

$PATH = /usr/kerberos/sbin:/usr/kerberos/bin:/usr/local/sbin:/usr/local/bin:/sbin:/bin:/usr/sbin:/usr/bin:/usr/X11R6/bin:/root/bin

$ b b

有任何想法或建议吗？我确定当运行cronjob，它没有lib路径或包括任何东西。我甚至尝试添加确切的路径

Any ideas or suggestions? I am certain when running the cronjob, it does not have a lib path or something included. I even tried adding the exact path

推荐答案

提示1：确保您在cron作业中具有完全相同的$ PATH： p>

Tip 1: Ensure you have exactly the same $PATH in the cron job:

cd /etc/parselog/
export PATH=/usr/kerberos/sbin:/usr/kerberos/bin:/usr/local/sbin:/usr/local/bin:/sbin:/bin:/usr/sbin:/usr/bin:/usr/X11R6/bin:/root/bin
php run_all.php >/dev/null

提示2：确保所有其他环境变量匹配。使用命令 env 转储环境，并将相应的导出添加到cron作业。

Tip 2: Make sure all other environment variables match as well. Dump the environment with the command env, and add the corresponding exports to your cron job.

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