在PHP中创建并执行cron作业 [英] Create and execute the cron job in PHP

问题描述

有类似的线程，我已经经历了。他们不会清除我的疑虑。

There are similar thread, I already went through. They don't clear my doubts please!

refresh.php

refresh.php

<?php

echo "This code will run every minute";
if(count!=1)
 count+=1;
else
 $count = 1;

echo $count;
?>

cron.php

<?php
    exec('echo -e "`crontab -l`\n30 1 * * * /opt/lamt/htdocs/refresh.php" | crontab -'); //to run at 1:30 am        
?>

1. 如何在晚上10:30运行？


2. 如何执行 cron.php ??

1. How to run this at 10:30 pm ?
2. How to execute cron.php ??

推荐答案

打开shell并输入：

Open shell and type this:

command="php /opt/lamt/htdocs/refresh.php"
job="30 22 * * * $command"
cat <(fgrep -i -v "$command" <(crontab -l)) <(echo "$job") | crontab -

上面的代码创建了一个cronjob来执行 / opt / lamt / htdocs /refresh.php 每天在 22.30 。

The above creates a cronjob that executes /opt/lamt/htdocs/refresh.php every day at 22.30.

command="php /opt/lamt/htdocs/refresh.php"
job="30 10 * * * $command"
cat <(fgrep -i -v "$command" <(crontab -l)) <(echo "$job") | crontab -

上面的代码创建了一个cronjob来执行 / opt / lamt / htdocs /refresh.php 每天在 10.30 。

The above creates a cronjob that executes /opt/lamt/htdocs/refresh.php every day at 10.30.

这是正确的 crontab 语法：

# * * * * *  command to execute
# ┬ ┬ ┬ ┬ ┬
# │ │ │ │ │
# │ │ │ │ │
# │ │ │ │ └───── day of week (0 - 7) (0 to 6 are Sunday to Saturday, or use names; 7 is Sunday, the same as 0)
# │ │ │ └────────── month (1 - 12)
# │ │ └─────────────── day of month (1 - 31)
# │ └──────────────────── hour (0 - 23)
# └───────────────────────── min (0 - 59)

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