用Python加密 [英] Encryption with Python

问题描述

我在Python中使用加密函数，我想使用公钥加密随机数。

I'm making an encryption function in Python and I want to encrypt a random number using a public key.

我想知道如果我使用Crypto包（ Crypto.publicKey.pubkey ）比我如何使用像...的方法。

I wish to know that if I use Crypto package (Crypto.publicKey.pubkey) than how can I use the method like...

def encrypt(self,plaintext,k)

> k 本身是一个随机数，就是这个意思的关键。

Here the k is itself a random number, is this mean the key. Can somebody help me with somewhat related?

推荐答案

您尝试使用公钥加密对话加密的会话/消息密钥的收件人？

Are you trying to encrypt a session/message key for symmetric encryption using the public key of the recipient? It might be more straightforward to use, say, SSH or TLS in those cases.

返回您的问题：

Me Too Crypto （M2Crypto）是关于openssl的一个很好的包装。

Me Too Crypto (M2Crypto) is a nice wrapper around openssl.

首先，您需要获取收件人的公钥：

First, you need to get the public key of the recipient:

recip = M2Crypto.RSA.load_pub_key(open('recipient_public_key.pem','rb').read())

现在您可以加密您的邮件：

Now you can encrypt your message:

plaintext = random_integer_you_want_to_encrypt
msg = recip.public_encrypt(plaintext,RSA.pkcs1_padding)

现在只有拥有收件人解密。

Now only someone with the private key of the recipient can decrypt it.

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