如何Gulp观看多个文件？ [英] How to Gulp-Watch Multiple files?

问题描述

我有这样的：

gulp.task('default', ['css', 'browser-sync'] , function() {

    gulp.watch(['sass/**/*.scss', 'layouts/*.css'], function() {
        gulp.run('css');
    });

});

但它不工作，因为它监视两个目录，sass和layouts目录的更改。

but it does not work, because it watches two directories, the sass and the layouts directory for changes.

如何使其工作，以便gulp监视那些目录中发生的任何事情？

How do I make it work, so that gulp watches anything that happens inside those directories?

，

乔治

推荐答案

gulp.task('default', ['css', 'browser-sync'] , function() {

    gulp.watch(['sass/**/*.scss', 'layouts/**/*.css'], ['css']);

});

sass / ** / * scss 和 layouts / ** / *。css 将监视每个目录和子目录对 .scss 和 .css 更改的文件。如果要将其更改为任何文件，请将最后一位 *。*

sass/**/*.scss and layouts/**/*.css will watch every directory and subdirectory for any changes to .scssand .css files that change. If you want to change that to any file make the last bit *.*

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