如何获取一个CSS选择器使用Selenium WebDriver？ [英] How to get a CSS selector using Selenium WebDriver?

问题描述

我正在尝试为横幅菜单中显示的元素创建动态元素贴图，包括为每个菜单显示的链接。
此映射将存储在 String [] [] 矩阵中，将用于不同的方法和测试。

I'm trying to create a dynamic "element map" of the elements displayed inside a banner menu including the link displayed for each menu. This map will be stored inside a String[][] matrix, which will be used for different methods and tests.

为此，我得到元素的 href 属性，并为菜单中显示的每个链接创建我自己的CSS选择器。这是我的代码创建CSS：

To do that I get the element's href attribute and create my own CSS selector for each link displayed in the menus. This is my the code to create the CSS:

CSS = (String)element.getAttribute("href").subSequence((element.getAttribute("href").length()-20), element.getAttribute("href").length());

CSS="a[href*='" + CSS +"']";

这很好，但我有一些链接运行一些JavaScript代码，我不能创建CSS选择器。

That works pretty well, but I have some links that run some JavaScript code and I cannot create the CSS selector for them.

有没有其他方法从WebElement获取CSS选择器？
使用Firebug我可以得到CSS路径。在具有WebElement的执行期间，我可以获得这个CSS路径吗？有任何其他建议吗？

Is there any onther way to get the CSS selector from a WebElement? Using Firebug I can get the CSS path. Could I get this CSS path during the execution having the WebElement? Any other suggestions?

推荐答案

答案是否。您不能从WebElement中提取CSS选择器。

The answer is No. You cannot extract a CSS selector from a WebElement.

为什么？因为WebElements本身由 By 类找到。如果由指定为 xpath ？它将如何填充CSS选择器？

Why? Because the WebElements themselves are found by the By class.. What if the By specified was xpath? How would it populate the CSS selector?

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