CSS:对列表上的伪元素之前的内容进行样式化 [英] CSS : Styling the content of before pseudo element on a list
问题描述
我试图为有序列表(无点,带半径的边框旋转45°)设置样式。
; div class =test>
< ol>
< li>< span>是测试< / span>< / li>
< li>< span>和< / span>< / li>
< / ol>
< / div>
和css
.test ol {
counter-reset:li;
list-style-type:none;
}
.test ol> li {
position:relative;
list-style:none;
}
.test ol> li:before {
content:counter(li);
counter-increment:li;
position:absolute;
top:-2px;
left:-24px;
width:21px;
color:#E2202D;
font-weight:bold;
font-family:Helvetica Neue,Arial,sans-serif;
text-align:center;
border:1px dotted#E2202D;
-webkit-border-radius:6px;
border-radius:6px;
-webkit-transform:rotate(45deg);
}
它给我那
这里是我阻塞...如何旋转边框不旋转数字里面?如何在css中为伪元素的内容设计样式?
感谢任何建议:)
没有办法单独旋转边框和文本。相反,您可以将数字和边界拆分为两个不同的伪元素::
之前和:
之后。 / p>
请参阅: http: //jsbin.com/agotuj/54/edit
.test ol {
counter-reset:li;
list-style-type:none;
}
.test ol> li {
position:relative;
list-style:none;
margin-bottom:20px;
padding-left:5px;
}
.test ol> li:before,.test ol> li:after {
position:absolute;
top:-2px;
left:-24px;
width:21px;
height:21px;
line-height:21px;
font-size:16px;
}
.test ol> li:before {
content:counter(li);
counter-increment:li;
color:#E2202D;
font-weight:bold;
font-family:Helvetica Neue,Arial,sans-serif;
text-align:center;
}
.test ol> li:after {
content:'';
border:1px dotted#E2202D;
border-radius:6px;
-webkit-transform:rotate(45deg);
-moz-transform:rotate(45deg);
-ms-transform:rotate(45deg);
-o-transform:rotate(45deg);
transform:rotate(45deg);
}
I'm trying to style an ordered list (no dot, a border with radius and rotate 45°)
<div class="test">
<ol>
<li><span>it's a test</span></li>
<li><span>and again</span></li>
</ol>
</div>
And the css
.test ol {
counter-reset: li;
list-style-type: none;
}
.test ol > li {
position:relative;
list-style:none;
}
.test ol > li:before {
content:counter(li);
counter-increment:li;
position:absolute;
top:-2px;
left:-24px;
width:21px;
color:#E2202D;
font-weight:bold;
font-family:"Helvetica Neue", Arial, sans-serif;
text-align:center;
border: 1px dashed #E2202D;
-webkit-border-radius:6px;
border-radius:6px;
-webkit-transform: rotate(45deg);
}
It give me that
And this is here i'm blocking... How to rotate the border without rotate the number inside ? How to style the content of a pseudo element in css ?
Thanks for any advice :)
There's no way to rotate the border and text separately. Instead, you can split the number and the border into two different pseudo-elements, :before
and :after
.
See: http://jsbin.com/agotuj/54/edit
.test ol {
counter-reset: li;
list-style-type: none;
}
.test ol > li {
position: relative;
list-style: none;
margin-bottom: 20px;
padding-left: 5px;
}
.test ol > li:before, .test ol > li:after {
position: absolute;
top: -2px;
left: -24px;
width: 21px;
height: 21px;
line-height: 21px;
font-size: 16px;
}
.test ol > li:before {
content: counter(li);
counter-increment: li;
color: #E2202D;
font-weight: bold;
font-family: "Helvetica Neue", Arial, sans-serif;
text-align: center;
}
.test ol > li:after {
content: '';
border: 1px dashed #E2202D;
border-radius: 6px;
-webkit-transform: rotate(45deg);
-moz-transform: rotate(45deg);
-ms-transform: rotate(45deg);
-o-transform: rotate(45deg);
transform: rotate(45deg);
}
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