AJAX后自行在PHP [英] AJAX Post to self in PHP

问题描述

我觉得这是一件我应该学会了现在，我敢肯定，这是小东西，我失踪，但我可以用澄清，以确保我的做法是正确的。

I feel like this is something that I should have learned by now, and I'm sure it's something small I'm missing, but I could use clarification to make sure my approach is correct.

我使用AJAX来数据发布到自这是一个包含PHP和HTML文件。我可以写PHP的罚款，但经过一个成功的Ajax后，我怎么只返回被通过PHP处理的数据，而不是剩余的HTML？它更好，只是张贴到一个单独的脚本？

I'm using AJAX to post data to self which is a file that contains php and html. I can write the php fine, but after a successful ajax post, how do I only return the data that is processed via php and not the remaining html? Is it better to just post to a separate script?

推荐答案

如果您有PHP处理的文件的开头POST请求，你可以做这样的事情：

If you have the PHP handling the POST request in the beginning of the file, you can just do something like this:

<?php
    if (isset($_POST['somevar'])) {
        /* do something */
        exit(0);
    }
?>

退出（）将停止页面加载在该行。

exit() will stop the loading of the page at that line.

我来说，认为最好是使用一个单独的脚本来处理动态AJAX请求。

I, for one, think it's better to be utilizing a separate script to deal with dynamic AJAX requests.

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