D3,x轴上的日期,数据是日期的宽度 [英] D3, dates on the x axis, data the width of a date
问题描述
我按日期显示数据。我想要的东西有点像这样:
I am visualizing data by date. I want something a bit like this:
关键是我要绘制的矩形是宽度的天。下面是我如何绘制矩形:
The point is that I want to draw rectangles that are the width of the days. Here's how I draw rectangles:
svg.selectAll(".my_class")
.data(my_data)
.enter()
.append("rect")
.attr({
"width": function(d) { return x_scale.rangeBand(); },
"height": function(d) { return h_scale(d.end - d.start); },
"x": function(d) { return x_scale(new Date(d.date)); },
"y": function(d) { return y_scale(d.end); },
"class": function(d) { return d.device; }
});
问题是为了得到合适的宽度,我最终声明了x_scale, p>
The problem is that in order to get the right width, I ended up declaring my x_scale thus
d3.scale.ordinal()
.domain(my_data.map(function (d) { return new Date(d.date); }))
.rangeRoundBands([0, image_width]);
。问题是,我没有看到一个方法来指定矩形宽度使用
d3.time.scale()$ c(注意在2,7和12之后的无间隙) $ c>。
解决方法是在期间的每一天在后端生成零高度矩形。这不是可怕的,但我觉得我应该能够做得更好。此外,我会失去诸如 .ticks(d3.time.weeks,1)
等细节,并自己旋转。
A work-around is to generate zero-height rectangles on the back end for every day in the period. This isn't that hideous, but I feel I should be able to do better. In addition, I'd lose niceties like .ticks(d3.time.weeks, 1)
and have to spin them myself.
任何指针?
推荐答案
最后,我发现的最简单的解决方案是使用顺序量表(有时为空)元素。
In the end, the simplest solution I found was to use an ordinal scale and provide (sometimes empty) elements for each date in the range.
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