同一个域策略的jQuery [英] Same domain policy jQuery

问题描述

我问过关于为什么大多数AJAX解决方案涉及如PHP一些后端语言的问题。

I had asked a question regarding why most ajax solutions involve some back-end language like PHP.

我被告知这是因为这样一个事实：Web浏览器不允许一个完整的JavaScript / jQuery的解决方案，因为同一个域策略。然而，下面绝对是code罚款运行：

I was told it was because of the fact that a web browser does not allow a complete javascript/jquery solution due to same domain policy. Yet the code below absolutely runs fine:

<script type="text/javascript">
        $(document).ready(function () {
            $("#1").click(function () {

                $.ajax({
                    type: "GET",
                    url: "http://api.wunderground.com/api/ac7e64a2f6e2d440/geolookup/conditions/q/IA/Cedar_Rapids.json",
                    dataType: "jsonp",
                    success: function (parsed_json) {
                        $('div').html("Current temperature in " + parsed_json.current_observation.temp_f);
                        alert(parsed_json.location.city);
                        var location = parsed_json['location']['city'];
                        var temp_f = parsed_json['current_observation']['temp_f'];
                        alert("Current temperature in " + location + " is: " + temp_f);
                    }
                });

            });

        });
</script>

因此​​，这是code不应该跑？我不明白这一点。

So is this code not supposed to run? I don't get it.

谢谢， 吉姆

推荐答案

只有JSONP请求工作跨域。你做这件事的方式是正确的！

only jsonp requests work cross-domain. Your way of doing it is correct!

1），您将无法访问其他域DOM元素或JavaScript对象（在IFRAME为例） 在这里看到我的回答：<一href="http://stackoverflow.com/questions/7617429/how-can-i-create-a-function-in-another-frame/7657264#7657264">How我可以在另一帧创建一个函数？

1) you can't access DOM elements or JavaScript Objects on other domain (in iframe for example) see my answer here: How can I create a function in another frame?

2）我们用来做这样的事情（见我的回答）从JS沟通，PHP和背部。 <一href="http://stackoverflow.com/questions/1678214/javascript-how-do-i-create-jsonp/5435042#5435042">JavaScript:如何创建JSONP？

2) we used to do things like this (see my answer) to communicate from JS to PHP and back. JavaScript: How do I create JSONP?

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