是否可以选择最后n个项目与nth孩子？ [英] Is it possible to select the last n items with nth-child?

问题描述

使用标准列表，我正在尝试选择最后2个列表项。我有 An + B 的各种排列，但似乎没有选择最后2个：

  li：nth-​​child（n + 2）{} / *从第二个开始选择* / 
 li：第n个孩子$ b li：nth-​​child（-n + 2）{} / *只选择前两个* / 
 li：nth-​​child ：：nth-​​last-child（）
 
 
我知道一个新的CSS3选择器， / code>但是我更喜欢在可能的情况下在几个浏览器中工作的东西（不关心IE特别）。
解决方案
  nth-last-child 听起来像是专门设计来解决这个问题，所以我怀疑是否有更兼容的替代品。但支持看起来体面的。
 
Using a standard list, I'm trying to select the last 2 list items. I've various permutations of An+B but nothing seems to select the last 2:
li:nth-child(n+2) {} /* selects from the second onwards */
li:nth-child(n-2) {} /* selects everything */
li:nth-child(-n+2) {} /* selects first two only */
li:nth-child(-n-2) {} /* selects nothing */
I'm aware of a new CSS3 selectors like :nth-last-child() but I'd prefer something that works in a few more browsers if possible (don't care about IE particularly).
解决方案
nth-last-child sounds like it was specifically designed to solve this problem, so I doubt whether there is a more compatible alternative. Support looks pretty decent, though.

                        
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