jQuery的，从PHP收到读JSON变量 [英] Jquery, reading JSON variables received from PHP

问题描述

抱歉，如果这是基本的，但我一直在处理搞清楚了这一点一整天，已经得到的地方，我所能做的一切，我需要使用jQuery和CakePHP（不知道CakePHP的事项本或者其任何PHP一样），我想回到从CakePHP的功能，jQuery的一个变量，我读了有关如何做到这一点，喜欢这里：

Sorry if this is basic, but I have been dealing with figuring this out all day and have gotten to where I can do everything I need with Jquery and cakephp (not sure if cakephp matters in this or if its same as any PHP), I want to return a variable from a cakephp function to jquery, I had read about how to do it, like here:

CakePHP的：

$test[ 'mytest'] = $test;
 echo json_encode($test);

和jQuery的：

$.ajax({
  type: 'POST',
  url: 'http://localhost/site1/utilities/ajax_component_call_handler',
  data: {
        component_function: component_function,
        param_array: param_array
        },
        dataType: "json",
  success: function(data) {
   // how do i get back the JSON variables? 
  }
});

我只是无法弄清楚如何获得一个或多个变量回内jQuery的有用的形式，我只是想变，所以我可以做任何其他事情，我一直在寻找什么，我可以通过搜索找到但它不是任何意见使它完全清楚，我..谢谢。

I just can't figure out how to get one or more variables back into usable form within jquery, I just want the variable so I can do whatever else with it, I've been looking at what I can find through searching but its not making it fully clear to me.. thanks for any advice.

推荐答案

您变量数据。

$.ajax({
  type: 'POST',
  url: 'http://localhost/site1/utilities/ajax_component_call_handler',
  data: {
        component_function: component_function,
        param_array: param_array
        },
        dataType: "json",
  success: function(data) {
   // how do i get back the JSON variables? 
      var values = eval( data ); //if you 100 % trust to your sources.
  }
});

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