什么JQuery选择器排除父项匹配给定选择器的项目？ [英] What JQuery selector excludes items with a parent that matches a given selector?

问题描述

我有

var $set = $('.foo,.bar').filter(
    function() {return $(this).parents('.baz').length < 1;});

作为选择所有其类为 foo 或 bar ，并且不从类 baz 的元素下降。是否有一个选择器将完成相同的事情，而不需要过滤lambda？

as a way to select all the elements whose classes are either foo or bar and who do not descend from an element whose class is baz. Is there a selector that will accomplish the same thing without the need for a filtering lambda?

<div class='foo'/><!--match this-->
<div class='bar'/><!--match this-->
<div class='baz'>
    <div class='foo'/> <!--don't match this-->
</div>

推荐答案

事实的真相是jQuery根本不有一个特别优雅的方式做你想要的。虽然混乱的答案工作，你必须怀疑复杂的选择器（这将是一个复杂的网页选择器一样慢）是否值得你更详细但更快的过滤器函数。这不是真的那么大的交易，我只是个人疲倦特别长，令人费解的选择器，当我可以避免它。

The truth of the matter is that jQuery simply does not have a particularly elegant way to do what you want. While chaos' answer does work, you have to wonder whether the complicated selector (that would be about as slow as a selector can be in a complicated webpage) is worth it over the more verbose but faster filter function you have. This is not really that big of a deal, I am just personally weary of particularly long, convoluted selectors when I can avoid it.

一个不同的选择是创建自己因为jQuery是真棒的：

A different option is to create your own selector, since jQuery is awesome:

jQuery.expr[':'].parents = function(a,i,m){
    return jQuery(a).parents(m[3]).length < 1;
};

$('.foo,.bar').filter(':parents(.baz)');

expr 地图是Sizzle的一部分选择器引擎和文档可以在这里找到： Sizzle Custom Pseudo-Selectors

The expr map is part of the Sizzle selector engine and documentation can be found here: Sizzle Custom Pseudo-Selectors

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