当使用querySelectorAll时,是否有一种方法来引用上下文节点的直接子节点,而不使用ID? [英] When using querySelectorAll, is there a way to reference the immediate children of the context node, without using IDs?
问题描述
说我有一个HTML结构,如
Say I have an HTML structure like
<div id="a">
<div id="b">
<div id="c"></div>
</div>
</div>
要使用querySelectorAll查询a的子节点,我可以做
To do a query for the children of "a" using querySelectorAll I can do something like
//Get "b", but not "c"
document.querySelectorAll('#a > div')
我的问题是:可以在没有ID的情况下节点直接?我尝试了
My question is: is it possible to do this without the ID, referencing the node directly? I tried doing
var a_div = document.getElementById('a')
a_div.querySelectorAll('> div') //<-- error here
但我得到一个错误告诉我,使用的是无效的。
but I get an error telling me that the selector I used is invalid.
如果有人想知道,我的真实用例会更复杂。 foo .bar .baz',所以我宁愿避免手动DOM遍历。目前,我添加一个临时的id到根div,但似乎是一个丑陋的黑客...
And in case anyone is wondering, my real use case would be something more complicated like '> .foo .bar .baz' so I would prefer to avoid manual DOM traversal. Currently I am adding a temporary id to the root div but that seems like an ugly hack...
推荐答案
't a way (yet)引用某个元素的所有子元素,而不使用对该元素的引用。因为>
是子组合器,表示父元素和子元素之间的关系,
No, there isn't a way (yet) to reference all childs of some element without using a reference to that element. Because >
is a child combinator, which represents a relationship between a parent and child element, a simple selector (a parent) is necessary (which is missing in you example).
在注释中, BoltClock说 选择器API第2级规范定义了一种方法 findAll
em>更改 ,其接受作为参数的可能被称为相对选择器(可以用组合器而不是复合选择器开始的选择器)。
当实现时,它可以如下使用:
In a comment, BoltClock said that the Selectors API Level 2 specification defines a method findAll
name may change "which accepts as an argument what will probably be known as a relative selector (a selector that can start with a combinator rather than a compound selector)".
When this is implemented, it can be used as follows:
a_div.findAll('> div');
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