Ajax请求python脚本 [英] ajax request to python script
本文介绍了Ajax请求python脚本的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我刚刚测试了一个脚本,我做。这是蟒蛇。我用ajax,发送请求和尝试,并得到结果。
i just tested out a script i made. it is in python. i use ajax, to send a request and try and get the result.
function ajaxFunction(){
var ajaxRequest;
var e = document.getElementById("ktype");
var ktype = e.options[e.selectedIndex].value;
var acookie = document.getElementById("acookie").value;
alert (ktype +"\n" + acookie);
try{
ajaxRequest = new XMLHttpRequest();
} catch (e){
try{
ajaxRequest = new ActiveXObject("Msxml2.XMLHTTP");
} catch (e) {
try{
ajaxRequest = new ActiveXObject("Microsoft.XMLHTTP");
} catch (e){
return false;
}
}
}
ajaxRequest.onreadystatechange = function(){
if (ajaxRequest.readyState < 4){
document.getElementById("resp").innerHTML = "<center><img src='loading.gif' style='max-width:60px; max-height:60px;'></center>";
}
if(ajaxRequest.readyState == 4){
document.getElementById("resp").innerHTML = ajaxRequest.responseText;
}
}
ajaxRequest.open("POST", "kindle.py", true);
ajaxRequest.setRequestHeader("Content-type","application/x-www-form-urlencoded");
ajaxRequest.send("amzcookie=" + acookie + "&ktype=" + ktype);
}
在python脚本使用CGI。没有Web框架,比如Django的。
the python script uses CGI. no web framework like django.
当我这样做要求它只是打印蟒蛇文件的内容。没有code被执行。
when i do this request it just prints the contents of the python file. no code is executed.
推荐答案
您应该使用 JQuery的
为...,而不是写你自己的 Ajax的
请求时,它可以写在一个行:
You should use JQuery
for that ... instead of writing your own Ajax
request, it can be written in a line:
$.post('link-to-my-python-script',{data},
function(answer){
// process your request here ..
});
您可以阅读更多有关在这里: JqueryPost
You can read more about that here: JqueryPost
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