使用PHP创建CSV文件 [英] Creating a CSV file with PHP
问题描述
我通过php创建一个csv文件,我从我的数据库获取一些值。
I'm creating a csv file via php and I'm getting some values from my database.
我获得了一个成功的值并生成了csv。
I'm getting a value successfully and generating the csv excellently.
我有一个像这样的值0012345和0051234
I have a value like this 0012345 and 0051234
我的问题是,当我查看我的csv文件中的数据,00不显示只有12345和51234。
My problem here is when I view the data in my csv file, the 00 is not displaying only the 12345 and 51234.
当我检查我的excel,我去格式单元格,它似乎它被设置为通用模式。它应该设置为Text,以便它将接受00作为数字的第一个数字。
When I check on my excel and I go to Format Cells, it seems it is set into General mode. It should be set into Text so that it would accept 00 as the first digit of the number.
这是我的代码:
$csv_filename="ePay.csv";
header("Cache-Control: maxage=1");
header("Pragma: public");
header("Content-Type: application/vnd.ms-excel");
header("Expires: 0");
header("Cache-Control: must-revalidate, post-check=0, pre-check=0");
header("content-disposition: attachment;filename=$csv_filename");
include("/includes/config.php");
$sql = "SELECT * FROM moneyroute where sender_country ='Nigeria' and status = 'new'";
#echo $sql;
$olu="AfrotradeGroup";
$result=mysql_query($sql);
if(mysql_num_rows($result)>0){
$fileContent="Beneficiary Name,Beneficiary Account No,Beneficiary Bank Code,Transaction Amount,Narration\n";
while($data=mysql_fetch_array($result))
{
$name_=$data['sender_first_name']." ".$data['sender_last_name'];
if($data['status']=='u')
$sta='Approved';
else
$sta='Pending';
$fileContent.= "".$data['receiver_first_name']." ".$data['receiver_last_name'].",".$data['accountno'].",".$data['sortcode'].",".$data['equal_currency'].",".$olu."\n";
}
$fileContent=str_replace("\n\n","\n",$fileContent);
echo $fileContent;
}
我得到这样的结果:
Ade you 67654578 97865 30151.52 AfrotradeGroup \
67654578应为067654578,97865应为097865
I'm getting a result like this: Ade you 67654578 97865 30151.52 AfrotradeGroup\ The 67654578 should be 067654578 and 97865 should be 097865
这个问题的解决方案是什么?
提前感谢并有一个美好的一天。
What's the solution for this problem? Thanks in advance and have a great day.
推荐答案
看来问题是你必须使用铸件运营商。
It seems the problem is that you have to use the casting operators.
$myText = (string)$myVar;
这种方式将变量用作文本而不是数字。
This way the variable is used as a text and not as a number.
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