使用regexp Ruby Capybara替换文本 [英] Replacing text with regexp Ruby Capybara

问题描述

我有一个问题已经连接到这个问题，但这个问题是一个不同的方法。

I have a question running already linked to this problem, but this question is for a different approach.

我在网页上有一个文本字符串，事务完成后的时间戳（hhmmss）。

I have a string of text on a webpage that produces includes a timestamp (hhmmss) after a transaction is complete.

我不能使用Time.now，因为处理时间取决于许多因素。

I can't use Time.now as the processing time varies depending on many factors.

页面上的文字是：

"Your transaction reference number is: 0 16123 (timestamp is here) A1"

我测试的文本：

expect(find(location)).to have_text trans_text

我可以将位置文本设置为变量：

Could I set the location text as a variable:

trans_text = find(location, text: 'Your transaction reference number is: 0 16123 (timestamp is here) A1')

然后用正则表达式替换时间戳，然后期望时间戳在两次之间？

then replace the timestamp with a regex then expect that timestamp to be between two times?

我已经尝试：

trans_text = find(location, text: 'Your transaction reference number is: 0 16123 (\d+) A1')

但没有快乐。我收到以下错误：

But had no joy. I get the following error:

Unable to find css "#main > div > div.section-content > div.two-col.retention-success > div.second-col > div.alert-complete > p" with text "Your retention certificate number is: 0 16123 (/d+) A1".

如何输入正则表达式来替换文本的时间戳部分？

How could I input a regex to replace the timestamp part of the text?

感谢

推荐答案

根据 Capybara文档：

text（String，Regexp） - 只找到包含此文本或匹配此正则表达式的元素

text (String, Regexp) — Only find elements which contain this text or match this regexp

通过正则表达式（而不是字符串）：

You have to search by regular expression (instead of a string):

find('p', text: /Your transaction reference number is: 0 16123 (\d+) A1/)

或在一个步骤中进行验证：

Or do verification in one step:

expect(page).to have_text /Your transaction reference number is: 0 16123 (\d+) A1/

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