如何在PHP中回传JSON [英] How to echo JSON in PHP

问题描述

我只需要一点帮助在PHP中使用cURL和JSON，因为我从来没有真正做到这一点。我想要完成的是采取点燃的付款，并回应它，也限制了最多的捐赠可以张贴最先捐赠。

I just need a little help with using cURL and JSON in PHP since I never actually got around to doing this. What I am trying to accomplish is to take the ign of the payment and echoing it, also limiting on how much can be posted by the latest donation first.

URL：< a href =http://api.buycraft.net/query?secret=83d043249170343dd048d4da62387f6cb39ed97f&action=payments =noreferrer> http://api.buycraft.net/query?secret=83d043249170343dd048d4da62387f6cb39ed97f&action=payments

推荐答案

如果你想对JSON数组进行编码或解码，你可以使用这些函数

if you want to encode or decode an array from or to JSON you can use these functions

$myJSONString = json_encode($myArray);
$myArray = json_decode($myString);

json_encode将生成一个JSON字符串，从一个
json_decode将产生一个Array，从一个形成良好的JSON字符串

json_encode will result in a JSON string, built from an (multi-dimensional) array. json_decode will result in an Array, built from a well formed JSON string

构建，你可以从API获取结果，只输出你想要的，例如：

with json_decode you can take the results from the API and only output what you want, for example:

echo $myArray['payload']['ign'];

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