在Python中帮助cURL [英] Help with cURL in Python

问题描述

我必须向服务器发送请求。在网站的API文档中，有一个在PHP中使用cURL的示例：

  $ ch = curl_init 
 curl_setopt（$ ch，CURLOPT_URL，'http://api.website.com'）; 
 curl_setopt（$ ch，CURLOPT_POST，1）; 
 curl_setopt（$ ch，CURLOPT_POSTFIELDS，request = $ wrapper）; 
 curl_setopt（$ ch，CURLOPT_RETURNTRANSFER，true）; 
; 
 $ data = curl_exec（$ ch）; 
 curl_close（$ ch）; 
  

但是我的应用程序是使用Python完成的，所以我试图写这样的东西， t work：

  req = urllib2.Request（url，formatted）
 response = urllib2.urlopen（req）
 html = response.read（）
 print html +\\\
\\\

  

你能帮我把PHP cURL程序的工作转换写成Python吗？

谢谢！

这是很尴尬，但...我唯一的问题，我的代码使用urllib和urllib2是...这个代码做一个GET，而不是一个POST！ p>

这里我使用Wireshark进行扫描：

1-使用urllib和urllib2

 超文本传输​​协议
 GET / HTTP / 1.1 \r\\\
 
 [聊天/序列]：GET / HTTP / 1.1 \r\\\
] 
 [消息：GET / HTTP / 1.1\r\\\
] 
 [严重级别：聊天] 
 [组：序列] 
请求方法：GET 
请求URI：/ 
请求版本：HTTP / 1.1 
接受编码：identity \r\\\
 
主机：api.apptrackr.org\r \\\
 
连接：close\r\\\
 
用户代理：Python-urllib / 2.6\r\\\
 
 \r\\\
 
  
 
 
 
 2-使用PyCurl 
 超文本传输​​协议
 POST / HTTP / 1.1 \r\\\
 
 [专家信息（聊天/序列）：POST / HTTP / 1.1\r\\\
] 
 [消息：POST / HTTP / 1.1 \r\\\
] 
 [严重级别：聊天] 
 [组：序列] 
请求方法：POST 
请求URI：/ 
请求版本：HTTP / 1.1 
用户代理：PycURL / 7.19.5\r\\\
 
主机：api.website.com\r\\\
 
接受：* / * \r\\\
 
 Content-Length：365 \r\\\
 
 [Content length：365] 
 Content-Type：application / x-www-form -urlencoded \r\\\
 
 \r\\\
 
基于行的文本数据：application / x-www-form-urlencoded 
 [truncated] request =％7B％22enc_key ％22％3A％22o37vOsNetKgprRE0VsBYefYViP4％2ByB3pjxfkfCYtpgiQ％2ByxONgkhhsxtqAwaXwCrrgx％2BPDuDtMRZNI1ez // 4Zw％3D％3D％22％2C％22format％22％3A％22RSA_RC4_Sealed％22％2C％22profile％22％3A％22Ldn％22％2C％22request％ 22％3A％22bQ％2BHm / 
  
所以代码工作，但它不适合我，需要一个POST，但我会更喜欢使用NOT PyCurl。 
任何想法？
 
 
 
非常感谢！
 
I have to POST a request to a server. In the API documentation of the website there is this example that uses cURL in PHP:
$ch = curl_init();
curl_setopt($ch, CURLOPT_URL, 'http://api.website.com');
curl_setopt($ch, CURLOPT_POST, 1);
curl_setopt($ch, CURLOPT_POSTFIELDS, "request=$wrapper");
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
;
$data = curl_exec($ch);
curl_close($ch);
But my app is done using Python, so I tried to write something like that but this code doesn't work:
req = urllib2.Request(url, formatted)  
response = urllib2.urlopen(req)  
html = response.read()  
print html+"\n\n"  
Can you help me write a working conversion of a PHP cURL program to Python?

Thank you!!
解决方案
It's quite embarrassing but... the only problem with my code that uses urllib and urllib2 is... that this code do a GET and not a POST !!!

Here my scan using Wireshark:

1- using urllib and urllib2
Hypertext Transfer Protocol
    GET / HTTP/1.1\r\n
        [Expert Info (Chat/Sequence): GET / HTTP/1.1\r\n]
            [Message: GET / HTTP/1.1\r\n]
            [Severity level: Chat]
            [Group: Sequence]
        Request Method: GET
        Request URI: /
        Request Version: HTTP/1.1
    Accept-Encoding: identity\r\n
    Host: api.apptrackr.org\r\n
    Connection: close\r\n
    User-Agent: Python-urllib/2.6\r\n
    \r\n
2- using PyCurl
Hypertext Transfer Protocol
    POST / HTTP/1.1\r\n
        [Expert Info (Chat/Sequence): POST / HTTP/1.1\r\n]
            [Message: POST / HTTP/1.1\r\n]
            [Severity level: Chat]
            [Group: Sequence]
        Request Method: POST
        Request URI: /
        Request Version: HTTP/1.1
    User-Agent: PycURL/7.19.5\r\n
    Host: api.website.com\r\n
    Accept: */*\r\n
    Content-Length: 365\r\n
        [Content length: 365]
    Content-Type: application/x-www-form-urlencoded\r\n
    \r\n
Line-based text data: application/x-www-form-urlencoded
    [truncated]         request=%7B%22enc_key%22%3A%22o37vOsNetKgprRE0VsBYefYViP4%2ByB3pjxfkfCYtpgiQ%2ByxONgkhhsxtqAwaXwCrrgx%2BPDuDtMRZNI1ez//4Zw%3D%3D%22%2C%22format%22%3A%22RSA_RC4_Sealed%22%2C%22profile%22%3A%22Ldn%22%2C%22request%22%3A%22bQ%2BHm/
so the code works, but it's not right for me because i need a POST, but i will prefer to use NOT PyCurl.
Any idea?

Thank you very much!!

                        
这篇关于在Python中帮助cURL的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！