如何使用curl在java和解析json响应 [英] How to use curl in java and parse json response

问题描述

我有一个curl命令，提供JSON响应。我想使用这个curl命令在java&在java中解析JSON响应。是否可以这样做？

I have a curl command that gives a JSON response. I want to use this curl command in java & parse the JSON response in java. Is it possible to do so??

编辑：
当我执行以下操作时：
public static void main（String [] args）throws Throwable {

When I do the following: public static void main(String[] args) throws Throwable {

    try {
        InputStream stream = Runtime.getRuntime().exec("curl --globoff --insecure --silent -u username:password -X GET -H 'Content-Type: application/json' \"http://ficcjira.xyz.com/rest/api/2/search?jql=project=ABC&fields=Timetracking\"").getInputStream();

        BufferedReader input = new BufferedReader(new InputStreamReader(stream), 1);

        input.readLine();
        input.read();
        input.read();

        DataReader reader = new JsonReader(input)
                .addField("TimeSpent", "//array/object/timespent")
                .addRecordBreak("//array/object");

        /*reader = new TransformingReader(reader)
                .add(new BasicFieldTransformer("TimeSpent").stringToDouble());*/

        DataWriter writer = new StreamWriter(System.out);

        JobTemplate.DEFAULT.transfer(reader, writer);

    } catch (IOException e) {
        // TODO Auto-generated catch block
        e.printStackTrace();
    }
}

我得到以下错误：无法运行程序curl：CreateProcess error = 2，系统找不到指定的文件

推荐答案

这是一个可怕的方式访问Jira Rest api。因为它是一个REST API，你可以在许多方面调用它。其中有些是：

This is a horrible way to access the Jira Rest api. Since it is a REST API, you can call it in many ways. Some of them are:

1. 保留Java的Java客户端。 https://marketplace.atlassian.com /plugins/com.atlassian.jira.jira-rest-java-client/server/overview

1. Rest Java Client for Java. https://marketplace.atlassian.com/plugins/com.atlassian.jira.jira-rest-java-client/server/overview

我有一些示例代码： https://github.com/somaiah/jrjc

1. Jersey：使用Jersey调用REST API并读取响应。

1. Jersey: Use Jersey to call the REST APIs and read the responses.

如果您使用Spring，可以使用RestTemplate。我在这里有一个小样本： https://github.com/somaiah/restTemplate

If you are using Spring, you can use the RestTemplate. I have a small sample here: https://github.com/somaiah/restTemplate

当然还有一大堆选择 - Restlet，Apache commons等等。

Of course there is a whole slew of options for you- Restlet, Apache commons and so on.

只有在从bash脚本调用此选项时，才应使用curl选项。在这种情况下，您可以使用jq（我喜欢的）解析响应 https://stedolan.github.io/jq /

You should use the curl option only if you are calling this from a bash script. In that case you can parse the response with jq (which I love) https://stedolan.github.io/jq/

这篇关于如何使用curl在java和解析json响应的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！