使用php检查主机的链接 [英] Checking link from a host with php

问题描述

我有几个链接，一些在rapidshare和一些在其他上传主机。
我如何检查链接上的文件是否仍然工作？

I got a few links, some on rapidshare and some on other uploading hosts. How can I check if the file on the link is still working?

我试过curl和file_get_contents。
在某些主机上curl正在工作，其他file_get_contents正在工作，但大多数不会返回页面源代码，所以我不能搜索字符串已删除或类似的东西。

I tried with curl and file_get_contents. On some hosts curl is working and on other file_get_contents is working but most won't return page source code so I can't search for the string "Deleted" or something like that.

有办法吗？

修改：这里是新的代码，仍然无法工作：

EDITED: Here is the new code, still won't work:

function curl_download($Url){
$ch = curl_init();
curl_setopt($ch, CURLOPT_URL, $Url);
$agent = "Mozilla/4.0 (compatible; MSIE 5.01; Windows NT 5.0)";
curl_setopt($ch, CURLOPT_USERAGENT, $agent);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
curl_setopt ($ch,CURLOPT_VERBOSE,false);
   curl_setopt($ch,CURLOPT_SSL_VERIFYPEER, FALSE);
   curl_setopt($ch,CURLOPT_SSLVERSION,3);
   curl_setopt($ch,CURLOPT_SSL_VERIFYHOST, FALSE);
curl_setopt($ch, CURLOPT_TIMEOUT, 0);
curl_setopt($ch, CURLOPT_FRESH_CONNECT, 1);
curl_setopt($ch, CURLOPT_FORBID_REUSE, 1);
$output = curl_exec($ch);
curl_close($ch);
return $output;

推荐答案

function Visit($url){
       $agent = "Mozilla/4.0 (compatible; MSIE 5.01; Windows NT 5.0)";
       $ch=curl_init();
       curl_setopt ($ch, CURLOPT_URL,$url );
       curl_setopt($ch, CURLOPT_USERAGENT, $agent);
       curl_setopt ($ch, CURLOPT_RETURNTRANSFER, 1);
       curl_setopt ($ch,CURLOPT_VERBOSE,false);
       curl_setopt($ch, CURLOPT_TIMEOUT, 5);
       curl_setopt($ch,CURLOPT_SSL_VERIFYPEER, FALSE);
       curl_setopt($ch,CURLOPT_SSLVERSION,3);
       curl_setopt($ch,CURLOPT_SSL_VERIFYHOST, FALSE);
       $page=curl_exec($ch);
       //echo curl_error($ch);
       $httpcode = curl_getinfo($ch, CURLINFO_HTTP_CODE);
       curl_close($ch);
       if($httpcode>=200 && $httpcode<300) return true;
       else return false;
}
if (Visit("http://www.google.com"))
       echo "Website OK"."n";
else
       echo "Website DOWN";

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