Python的subprocess.Popen（）结果不同于命令行？ [英] Python's subprocess.Popen() results differ from command line?

问题描述

在Windows 7 x32上使用Cygwin，在VS解决方案目录中， find 命令生成正确的结果：

  $ find。 -iname* .sln
 ./ProjName.sln 
  

Python的 subprocess.Popen（）似乎与 * 匹配：

 >>> import subprocess 
>>>> print subprocess.Popen（['find'，'。'，'-iname'，'* .sln']，
 ... stdout = subprocess.PIPE，shell = True）.communicate 0] 
。 
 ./.git 
 ./.git/COMMIT_EDITMSG 
 ./.git/config 
 ./.git/description 
< snip> 
  

我的 Popen（）

解决方案

以下适用于我：

 >>> import subprocess 
>>>> print subprocess.Popen（['find'，'。'，'-iname'，'* .sln']，
 ... stdout = subprocess.PIPE，shell = False）.communicate 
  

请注意 *。sln 和 shell 设置为 False 。

这确保 *。sln 被传递给 find 逐字，并且不由shell扩展。 p>

编辑：以下内容也可以使用：

 >>>> print subprocess.Popen（['find。-iname* .sln']，
 ... stdout = subprocess.PIPE，shell = True）.communicate（）[0] 
  

Using Cygwin on Windows 7 x32, in a VS solution directory, the find command produces correct results:

$ find . -iname "*.sln"
./ProjName.sln

but the same command with Python's subprocess.Popen() seems to be matching on * alone:

>>> import subprocess
>>> print subprocess.Popen(['find', '.', '-iname', '"*.sln"'],
...     stdout=subprocess.PIPE, shell=True).communicate()[0]
.
./.git
./.git/COMMIT_EDITMSG
./.git/config
./.git/description
<snip>

What's wrong with myPopen() call?

解决方案

The following works for me:

>>> import subprocess
>>> print subprocess.Popen(['find', '.', '-iname', '*.sln'],
...     stdout=subprocess.PIPE, shell=False).communicate()[0]

Note the removal of double quotes around *.sln and the setting of shell to False.

This makes sure that the *.sln is passed to find verbatim and is not expanded by the shell.

edit: The following also works:

>>> print subprocess.Popen(['find . -iname "*.sln"'],
...     stdout=subprocess.PIPE, shell=True).communicate()[0]

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