如何在d3.svg.axis中定义最大量的ticks [英] How can I define a maximal amount of ticks in a d3.svg.axis

问题描述

我有问题，我的 d3.svg.axis 的标签有时重叠。

I have the problem that the labels of my d3.svg.axis are sometimes overlapping. Therefor I would like to reduce the maximal amount of ticks and labels to a certain amount.

我似乎找不到一个解决方案在 API文档。

I can not seem to find a solution in the API documentation.

我不能使用 axis .tickValues（），因为范围是动态的，可以从几个小时到几年。

I can not use axis.tickValues() because the range is dynamic and can go from several hours to several years.

我试过使用 axis.ticks（9）但它似乎没有效果。您可以查看 bl.ocks.org/3181719 上的示例。

I have tried using axis.ticks(9) but it does not seem to have an effect. You can look at an example on bl.ocks.org/3181719.

推荐答案

这两个应该为你做。只需指定 axis.ticks（10）即可指定记号数或 axis.tickValues（[1,2,4]）

One of these two should do it for you. Just specify axis.ticks(10) to specify the number of tick marks or axis.tickValues([1,2,4]) to specify the actual tick marks that should appear.

由于您使用的是日期，因此您需要执行以下操作：

Since you are using dates, you'll need to do something like this:

 .ticks(d3.time.weeks, 2)

您可以访问 https://github.com/mbostock，了解有关时间间隔的详情/ d3 / wiki /时间间隔。您可以在 http://bl.ocks.org/1962173 上查看有关如何执行此操作的示例，以根据

You can read more about time intervals at https://github.com/mbostock/d3/wiki/Time-Intervals. You can see an example about how I do this at http://bl.ocks.org/1962173 to update the ticks based on the length of time being shown.

if ((maxExtent - minExtent) > 1468800000) {
    x1DateAxis.ticks(d3.time.mondays, 1).tickFormat(d3.time.format('%a %d'))
    x1MonthAxis.ticks(d3.time.mondays, 1).tickFormat(d3.time.format('%b - Week %W'))        
}
else if ((maxExtent - minExtent) > 172800000) {
    x1DateAxis.ticks(d3.time.days, 1).tickFormat(d3.time.format('%a %d'))
    x1MonthAxis.ticks(d3.time.mondays, 1).tickFormat(d3.time.format('%b - Week %W'))
}
else {
    x1DateAxis.ticks(d3.time.hours, 4).tickFormat(d3.time.format('%I %p'))
    x1MonthAxis.ticks(d3.time.days, 1).tickFormat(d3.time.format('%b %e'))
}

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