D3力有向图,根据数据和值给出不同的形状? [英] D3 force directed graph, different shape according to data and value given?
问题描述
我制作了一个强制有向图,我想改变包含entity:company
的数据的节点形状,以便它们具有矩形形状,
I've made a force directed graph and I wanted to change shape of nodes for data which contains "entity":"company"
so they would have rectangle shape, and other one without this part of data would be circles as they are now.
你可以在这里看到我的只有圆形节点的工作示例: http://jsfiddle.net/dzorz/uWtSk/
You can see my working example with only circle nodes here: http://jsfiddle.net/dzorz/uWtSk/
ve尝试添加如果else
语句在部分代码中添加矩形,其中我追加形状到节点像这样:
I've tried to add rectangles with if else
statement in part of code where I append shape to node like this:
function(d)
{
if (d.entity == "company")
{
node.append("rect")
.attr("class", function(d){ return "node type"+d.type})
.attr("width", 100)
.attr("height", 50)
.call(force.drag);
}
else
{
node.append("circle")
.attr("class", function(d){ return "node type"+d.type})
.attr("r", function(d) { return radius(d.value) || 10 })
//.style("fill", function(d) { return fill(d.type); })
.call(force.drag);
}
}
但是我没有得到任何形状任何节点。
But then I did not get any shape at all on any node.
什么是正确的设置方式?
What Is a proper way to set up this?
整个代码看起来像这样:
脚本:
The whole code looks like this: script:
var data = {"nodes":[
{"name":"Action 4", "type":5, "slug": "", "value":265000},
{"name":"Action 5", "type":6, "slug": "", "value":23000},
{"name":"Action 3", "type":4, "slug": "", "value":115000},
{"name":"Yahoo", "type":1, "slug": "www.yahoo.com", "entity":"company"},
{"name":"Google", "type":1, "slug": "www.google.com", "entity":"company"},
{"name":"Action 1", "type":2, "slug": "",},
{"name":"Action 2", "type":3, "slug": "",},
{"name":"Bing", "type":1, "slug": "www.bing.com", "entity":"company"},
{"name":"Yandex", "type":1, "slug": "www.yandex.com)", "entity":"company"}
],
"links":[
{"source":0,"target":3,"value":10},
{"source":4,"target":3,"value":1},
{"source":1,"target":7,"value":10},
{"source":2,"target":4,"value":10},
{"source":4,"target":7,"value":1},
{"source":4,"target":5,"value":10},
{"source":4,"target":6,"value":10},
{"source":8,"target":4,"value":1}
]
}
var w = 560,
h = 500,
radius = d3.scale.log().domain([0, 312000]).range(["10", "50"]);
var vis = d3.select("body").append("svg:svg")
.attr("width", w)
.attr("height", h);
vis.append("defs").append("marker")
.attr("id", "arrowhead")
.attr("refX", 17 + 3) /*must be smarter way to calculate shift*/
.attr("refY", 2)
.attr("markerWidth", 6)
.attr("markerHeight", 4)
.attr("orient", "auto")
.append("path")
.attr("d", "M 0,0 V 4 L6,2 Z"); //this is actual shape for arrowhead
//d3.json(data, function(json) {
var force = self.force = d3.layout.force()
.nodes(data.nodes)
.links(data.links)
.distance(100)
.charge(-1000)
.size([w, h])
.start();
var link = vis.selectAll("line.link")
.data(data.links)
.enter().append("svg:line")
.attr("class", function (d) { return "link" + d.value +""; })
.attr("x1", function(d) { return d.source.x; })
.attr("y1", function(d) { return d.source.y; })
.attr("x2", function(d) { return d.target.x; })
.attr("y2", function(d) { return d.target.y; })
.attr("marker-end", function(d) {
if (d.value == 1) {return "url(#arrowhead)"}
else { return " " }
;});
function openLink() {
return function(d) {
var url = "";
if(d.slug != "") {
url = d.slug
} //else if(d.type == 2) {
//url = "clients/" + d.slug
//} else if(d.type == 3) {
//url = "agencies/" + d.slug
//}
window.open("//"+url)
}
}
var node = vis.selectAll("g.node")
.data(data.nodes)
.enter().append("svg:g")
.attr("class", "node")
.call(force.drag);
node.append("circle")
.attr("class", function(d){ return "node type"+d.type})
.attr("r", function(d) { return radius(d.value) || 10 })
//.style("fill", function(d) { return fill(d.type); })
.call(force.drag);
node.append("svg:image")
.attr("class", "circle")
.attr("xlink:href", function(d){ return d.img_href})
.attr("x", "-16px")
.attr("y", "-16px")
.attr("width", "32px")
.attr("height", "32px")
.on("click", openLink());
node.append("svg:text")
.attr("class", "nodetext")
.attr("dx", 0)
.attr("dy", ".35em")
.attr("text-anchor", "middle")
.text(function(d) { return d.name });
force.on("tick", function() {
link.attr("x1", function(d) { return d.source.x; })
.attr("y1", function(d) { return d.source.y; })
.attr("x2", function(d) { return d.target.x; })
.attr("y2", function(d) { return d.target.y; });
node.attr("transform", function(d) { return "translate(" + d.x + "," + d.y + ")"; });
});
//});
css:
.link10 { stroke: #ccc; stroke-width: 3px; stroke-dasharray: 3, 3; }
.link1 { stroke: #000; stroke-width: 3px;}
.nodetext { pointer-events: none; font: 10px sans-serif; }
.node.type1 {
fill:brown;
}
.node.type2 {
fill:#337147;
}
.node.type3 {
fill:blue;
}
.node.type4 {
fill:red;
}
.node.type5 {
fill:#1BC9E0;
}
.node.type6 {
fill:#E01B98;
}
image.circle {
cursor:pointer;
}
您可以编辑我的jsfiddle链接在开头的帖子...
You can edit my jsfiddle linked on beginning of post...
推荐答案
解决方案: http://jsfiddle.net/Bull/4btFx/1/
我得到这个工作通过添加一个类到每个节点,然后使用 selectAll为每个类添加形状。在下面的代码中,我添加了一个类node和我的JSON(d.type)返回的类是rect或ellipse。
I got this to work by adding a class to each node, then using "selectAll" for each class to add the shapes. In the code below, I'm adding a class "node" and a class returned by my JSON (d.type) which is either "rect" or "ellipse".
var node = container.append("g")
.attr("class", "nodes")
.selectAll(".node")
.data(graph.nodes)
.enter().append("g")
.attr("class", function(d) {
return d.type + " node";
})
.call(drag);
然后您可以为每个类的所有元素添加形状:
Then you can add the shape for all elements of each class:
d3.selectAll(".rect").append("rect")
.attr("width", window.nodeWidth)
.attr("height", window.nodeHeight)
.attr("class", function(d) {
return "color_" + d.class
});
d3.selectAll(".ellipse").append("rect")
.attr("rx", window.nodeWidth*0.5)
.attr("ry", window.nodeHeight*0.5)
.attr("width", window.nodeWidth)
.attr("height", window.nodeHeight)
.attr("class", function(d) {
return "color_" + d.class
});
在上面的例子中,我使用半径的矩形来绘制椭圆,因为它们以相同的方式居中作为矩形。但它也适用于其他形状。在jsfiddle我链接,中心关闭,但形状是正确的。
In the above example, I used rectangles with radius to draw the ellipses since it centers them the same way as the rectangles. But it works with other shapes too. In the jsfiddle I linked, the centering is off, but the shapes are right.
这篇关于D3力有向图,根据数据和值给出不同的形状?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!