使用data.table的简单频率表 [英] Simple frequency tables using data.table

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问题描述

我正在寻找一种通过data.table执行简单聚合/计数的方法。



考虑虹膜数据,每个物种有50个观察值。为了计算每个物种的观测数据,我必须总结一个列而不是物种,例如Sepal.Length。

  (data.table)
dt = as.data.table(iris)
dt [,length(Sepal.Length),Species]

我觉得这很困惑,因为它看起来像我在Sepal.Length上做一些事情,乍一看,真的只有物种是重要的。



这是我想说的,但我没有得到有效的输出:

  dt [,length(Species),Species] 



正确的输入和输出, h2>

 > dt [,length(Sepal.Length),Species] 
种类V1
1:setosa 50
2:versicolor 50
3:virginica 50



输入和输出不正确,但更漂亮:



 > dt [,length(Species),Species] 
种类V1
1:setosa 1
2:versicolor 1
3:virginica 1

解决方案

p> data.table 有一些符号,可以在 j 表达式中使用。值得注意的是




  • .N 会给出每组中的行数。<$ c



请参阅?data.table c>


高级:按分组或i,符号.SD,.BY和.N可以用在j表达式中,定义如下。



....



.N是一个整数,长度为1,包含组中的行数。


例如:

  dt [,.N,by = Species] 

种类N
1:setosa 50
2:versicolor 50
3:virginica 50


I'm looking for a way to do simple aggregates / counts via data.table.

Consider the iris data, which has 50 observations per species. To count the observations per species I have to summaries over a column other than species, for example "Sepal.Length".

library(data.table)
dt = as.data.table(iris)
dt[,length(Sepal.Length), Species]

I find this confusing because it looks like I'm doing something on Sepal.Length at first glance, when really it's only Species that matters.

This is what I would prefer to say, but I don't get valid output:

dt[,length(Species), Species]

Correct input and output, but clunky code:

> dt[,length(Sepal.Length), Species]
Species V1
1:     setosa 50
2: versicolor 50
3:  virginica 50

Incorrect input and output, but nicer code:

> dt[,length(Species), Species]
Species V1
1:     setosa  1
2: versicolor  1
3:  virginica  1

Is there an elegant way around this?

解决方案

data.table has a couple of symbols that can be used within the j expression. Notably

  • .N will give you the number of number of rows in each group.

see ?data.table under the details for by

Advanced: When grouping by by or by i, symbols .SD, .BY and .N may be used in the j expression, defined as follows.

....

.N is an integer, length 1, containing the number of rows in the group.

For example:

dt[, .N ,by = Species]

     Species  N
1:     setosa 50
2: versicolor 50
3:  virginica 50

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