mySQL - 使用三个表中的数据和列创建新表 [英] mySQL - Create a New Table Using Data and Columns from Three Tables

问题描述

我正在尝试创建一个新表，该表将包含来自三个现有表的所选数据。

现有的三个表设置如下，所需的结果位于底部：

 人
 id last_name first_name电子邮件
 1史密斯弗雷德Fred @ .. 
 2琼斯汤姆汤姆@ .. 
 3 Doe简简@ 
 
 taxonomy 
 id taxonomy 
 1 age 
 2 gender 
 3 height 
 
详细信息
 id person_id detail_id内容
 1 1 1 36 
 2 1 2 M 
 3 1 3 5'10
 4 2 1 29 
 5 2 2 M 
 6 2 3 6'3
 7 3 1 27 
 8 3 2 F 
 9 3 3 5'8
 
 
新表
 id last_name first_name email age 
 1 Smith Fred Fred @ .. 36 
 2 Jones Tom Tom @ .. 29 
 3 Doe Jane Jane @ .. 27 
  
 
 
 
感谢您的帮助！
解决方案
你需要做一个3-way JOIN：
  CREATE TABLE new_table AS 
 SELECT p。*，d。内容AS age 
 FROM people AS p 
 JOIN详细信息AS d ON d.person_id = p.id 
 JOIN分类法AS t ON t.id = d.detail_id 
 WHERE t。 taxonomy ='age'
  
  DEMO  
 
 
 
或者如果您已经创建了表格，可以执行：
  INSERT INTO new_table（id，last_name，first_name，email，age）
 SELECT p.id，p.last_name，p。 first_name，p.email，d.content AS age 
 FROM people AS p 
 JOIN详细信息AS d ON d.person_id = p.id 
 JOIN分类法AS t ON t.id = d。 detail_id 
 WHERE t.taxonomy ='age'
  
要获得多个属性，分别为每个属性分别加入细节和分类表：
  CREATE TABLE new_table AS 
 SELECT p。*，d1 .content AS age，d2.content AS gender，d3.content AS height 
 FROM people AS p 
 JOIN详细信息AS d1 ON d1.person_id = p.id 
 JOIN分类AS​​ t1 ON t1 .id = d1.detail_id 
 JOIN详细信息AS d2 ON d2.person_id = p.id 
 JOIN分类AS​​ t2 ON t2.id = d2.detail_id 
 JOIN详细信息AS d3 ON d3.person_id = p.id 
 JOIN taxonomy AS t3 ON t3.id = d3.detail_id 
 WHERE t1.taxonomy ='age'AND t2.taxonomy ='gender'AND t3.taxonomy ='height'
  
 
I am trying to create a new table that will consist of selected data from three existing tables. 

The three existing tables are set up as following, and my desired result is at the bottom:
people
id      last_name   first_name  email
1       Smith       Fred        Fred@..
2       Jones       Tom         Tom@..
3       Doe         Jane        Jane@..

taxonomy
id      taxonomy    
1       age
2       gender
3       height

details
id      person_id   detail_id   content
1       1           1           36
2       1           2           M
3       1           3           5'10"
4       2           1           29
5       2           2           M
6       2           3           6'3"
7       3           1           27
8       3           2           F
9       3           3           5'8"


New Table
id      last_name   first_name  email   age
1       Smith       Fred        Fred@.. 36
2       Jones       Tom         Tom@..  29
3       Doe         Jane        Jane@.. 27
Thanks in advance for your help!
解决方案
You need to do a 3-way JOIN:
CREATE TABLE new_table AS
SELECT p.*, d.content AS age
FROM people AS p
JOIN details AS d ON d.person_id = p.id
JOIN taxonomy AS t ON t.id = d.detail_id
WHERE t.taxonomy = 'age'
DEMO

Or if you've already created the table, you can do:
INSERT INTO new_table (id, last_name, first_name, email, age)
SELECT p.id, p.last_name, p.first_name, p.email, d.content AS age
FROM people AS p
JOIN details AS d ON d.person_id = p.id
JOIN taxonomy AS t ON t.id = d.detail_id
WHERE t.taxonomy = 'age'
To get multiple attributes, you have to join with the details and taxonomy tables separately for each attribute:
CREATE TABLE new_table AS
SELECT p.*, d1.content AS age, d2.content AS gender, d3.content AS height
FROM people AS p
JOIN details AS d1 ON d1.person_id = p.id
JOIN taxonomy AS t1 ON t1.id = d1.detail_id
JOIN details AS d2 ON d2.person_id = p.id
JOIN taxonomy AS t2 ON t2.id = d2.detail_id
JOIN details AS d3 ON d3.person_id = p.id
JOIN taxonomy AS t3 ON t3.id = d3.detail_id
WHERE t1.taxonomy = 'age' AND t2.taxonomy = 'gender' AND t3.taxonomy = 'height'


                        
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