致命错误：调用未定义的函数mysqli_result（） [英] Fatal error: Call to undefined function mysqli_result()

问题描述

有人可以告诉我为什么这不工作，当我试图将我的旧sql切换到sqli：

Can someone please tell me why this doesnt work, when I tried to switch my old sql to sqli:

$query = "SELECT * FROM `product_category`";
$result = mysql_query($query, $connect) or die("could not perform query: " . mysql_error());
$num_rows = mysql_num_rows($result);

for ($i=0; $i < $num_rows; $i++)
{
    $ID = mysql_result($result,$i,"ID");
    $name = mysql_result($result,$i,"name");
    $description = mysql_result($result,$i,"description");

到：

$query = ("SELECT * FROM `product_category`");
$result = mysqli_query($connect, $query) or die("could not perform query");
$num_rows = mysqli_num_rows($result);

for ($i=0; $i < $num_rows; $i++)
{
    $ID = mysqli_result($result, "ID");
    $name = mysqli_result($result,$i,"name");
    $description = mysqli_result($result,$i,"description");`

它总是给我一个错误：致命错误：调用未定义的函数mysqli_result（）

it keeps giving me an error of: "Fatal error: Call to undefined function mysqli_result()"

推荐答案

种类的代码。这是非常低效率。请改用 mysqli_fetch_assoc（）：

Don't use this kind of code. It's highly inefficient. Use mysqli_fetch_assoc() instead:

while($row = mysqli_fetch_assoc($result)) {
   $id = $row['ID'];
   $name = $row['name']; 
   etc..
}

一个SINGLE数据库操作，而不是3 +您正在尝试。

One SINGLE database operation, rather than the 3+ you're trying to do.

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