codeigniter - 数据库：如何使用单个更新查询更新多个表 [英] codeigniter - database : how to update multiple tables with a single update query

问题描述

我在codeigniter论坛上看到 this

I saw this on the codeigniter forum

考虑下面的代码

UPDATE a
INNER JOIN b USING (id)
SET a.firstname='Pekka', a.lastname='Kuronen',
b.companyname='Suomi Oy',b.companyaddress='Mannerheimtie 123, Helsinki Suomi'
WHERE a.id=1; 

这就是你如何在Codeigniter中做的

This is how you would apparently do it in Codeigniter

$this->db->set('a.firstname', 'Pekka');
$this->db->set('a.lastname', 'Kuronen');
$this->db->set('b.companyname', 'Suomi Oy');
$this->db->set('b.companyaddress', 'Mannerheimtie 123, Helsinki Suomi');
$this->db->where('a.id', 1);
$this->db->join('table2 as b', 'a.id = b.id');
$this->db->update('table as a');

这在现实中不起作用。我已经看了一个SQL，这产生，结果甚至不提到连接。

this does not work in reality. I have had a look a the SQL which this produces and the results do not even mention the join.

有没有人知道如何使用Codeigniter的活动记录数据库类进行连接更新？

推荐答案

我发现的一个解决方案是删除连接，并将连接条件移动到一个'where'函数，还需要更改更新字符串包含新表格。

One solution I have found is to remove the join altogether and move the join condition into a 'where' function, also you will need to change the update string to include the new table.

$this->db->set('a.firstname', 'Pekka');
$this->db->set('a.lastname', 'Kuronen');
$this->db->set('b.companyname', 'Suomi Oy');
$this->db->set('b.companyaddress', 'Mannerheimtie 123, Helsinki Suomi');

$this->db->where('a.id', 1);
$this->db->where('a.id = b.id');
$this->db->update('table as a, table2 as b');

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