替代在MYSQL中的SubQuery中使用LIMIT关键字 [英] Alternative to using LIMIT keyword in a SubQuery in MYSQL
问题描述
我有一个表TEST,包含以下列:
code_ver(VARCHAR)
suite(VARCHAR)
date(DATE)
现在我想选择10行,有不同的值code_ver&因此我写了以下查询:
<$ p $ p>
select *
from test
其中code_ver IN(select DISTINCT code_ver
from test
其中code_ver NOT LIKE'%DevBld%'
ORDER by date DESC LIMIT 10);
这个查询应该是理想的工作,但我的MySQL版本说:这个版本的MySQL还没有支持LIMIT& IN / ALL / ANY / SOME子查询
有人可以建议我替换此查询吗?
解决方案你得到的错误并不完全是因为MySQL的版本。我认为所有版本支持。您必须更改LIMIT 10位置,并将其放在)之后。让我知道如果它为你工作。
> SELECT * FROM test where name IN(
SELECT DISTINCT name
FROM projects
WHERE name NOT LIKE%DevBld%
ORDER by date_created DESC
)LIMIT 10 ;
更新:请尝试以下方法,以这种方式工作:
SELECT * FROM automation.e2e_projects WHERE name IN(
SELECT DISTINCT name
FROM automation.e2e_projects
WHERE name NOT LIKE %DevBld%
)ORDER by date_created DESC LIMIT 10;
I have a table TEST with the following columns :
code_ver (VARCHAR)
suite (VARCHAR)
date (DATE)
Now I want to select 10 rows with a distinct value of code_ver & code_ver NOT LIKE '%DevBld%' sorted by date desc.
So I wrote the following query:
select *
from test
where code_ver IN (select DISTINCT code_ver
from test
where code_ver NOT LIKE '%DevBld%'
ORDER by date DESC LIMIT 10);
This query should ideally work, but my version of MySQL says : This version of MySQL doesn't yet support 'LIMIT & IN/ALL/ANY/SOME subquery'
Can someone suggest me an alternative to this query?
解决方案 The error you are getting is not exactly because of the version of MySQL. I think all versions support that. You have to change the LIMIT 10 place and place it after ")". Let me know if it works for you. I ran the bellow one on mine and it works.
E.g.
SELECT * FROM test where name IN (
SELECT DISTINCT name
FROM projects
WHERE name NOT LIKE "%DevBld%"
ORDER by date_created DESC
) LIMIT 10;
Update: Try the one below, this way order would work:
SELECT * FROM automation.e2e_projects WHERE name IN (
SELECT DISTINCT name
FROM automation.e2e_projects
WHERE name NOT LIKE "%DevBld%"
) ORDER by date_created DESC LIMIT 10;
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