FOSUserBundle(登录/注册)+ AJAX + Symfony2的 [英] FOSUserBundle (login / register) + AJAX + Symfony2
问题描述
我装 FOSUserBundle
我的的Symfony2
的网站,我overwrited登录和注册页面。它的工作非常好,但现在,我有另外一个问题:
I installed FOSUserBundle
on my Symfony2
website and I overwrited the login and register pages. It's working very well, but now, I have another issue :
将弹出与 AJAX
检查登录和注册部分,具有不同的路线,控制器,工作等。
Making a pop up with an AJAX
check for the login and register part, working with the different routes, controllers, etc.
如何做到这一点的最好方法是什么?
How to do that the best way ?
我的弹出是 login.html.twig
页的一个简单的引导模式 FOSUserBundle
,这里是$ C $的c中的模体
为登录的一部分(我将使用登记表的寄存器部分):
My pop up is a simple bootstrap modal of login.html.twig
page for FOSUserBundle
, here is the code of the modal-body
for the login part (I will use the register form for the register part) :
<div class="modal-body">
{% trans_default_domain 'FOSUserBundle' %}
{% block fos_user_content %}
<form action="{{ path("fos_user_security_check") }}" method="post">
<input type="hidden" name="_csrf_token" value="{{ csrf_token }}" />
<label for="username">{{ 'security.login.username'|trans }}</label>
<input type="text" id="username" name="_username" value="" required="required" />
<label for="password">{{ 'security.login.password'|trans }}</label>
<input type="password" id="password" name="_password" required="required" />
<br /><br />
<input type="submit" id="_submit" name="_submit" value="{{ 'security.login.submit'|trans }}" />
</form>
{% endblock fos_user_content %}
</div>
我已经搜查计算器及其他网站,但没有找到很好的答案我一直在寻找。
I already searched on StackOverflow and other websites but didn't find the good answer I was looking for.
感谢你。
推荐答案
没有当您使用AJAX标记
no token when you use AJAX
user=$('#username').val();
pass=$('password').val();
$.ajax(
{
type: "POST",
url: "{{ path ('your-rout')}}",
data: {'user': user,'pass':pass},
beforeSend: function() {
},
success: function(json) {}
});
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