如何在不同的bin中切割一个数字,并用新的bin来扩展数据框? [英] How to cut a number in different bin and expand the data frame with the new bins?
问题描述
bin.size = 100
df = data.frame(x = c(300,400),$ b $ = c(sca1,sca2))
cut(df $ x,seq(0,400,bin.size),
include.lowest = TRUE)
给我
[1 ](200,300)(300,400)
等级:[0,100](100,200](200,300)(300,400)
但是我想要这样的东西:
bin y
1(0,100] sca1
2(100,200] sca1
3(200,300)sca1
4(0,100)sca2
4(0,100] sca2
5(100,200] sca2
6(200,300)sca2
7(300,400) sca2
我想这样做,因为我想计算输入的数值为100例如:
df2 = data.frame(snp = c(1,2,10,100,1,2,14, 16.399)
sca = c(sca1,sca1,sca1,sca1,sca2,sca2,sca2,sca2 $ b df2
snp sca
1 1 sca1
2 2 sca1
3 10 sca1
4 100 sca1
5 1 sca2
6 2 sca2
7 14 sca2
8 16 sca2
9 399 sca2
snp可能是向量sca1中的位置。
最终目标是获得这样的东西:
bin y
1(0,100] sca1 4
2(100,200] sca1 0
3(200,300)sca1 0
4(0,100] sca2 4
5(100,200] sca2 0
6(200,300)sca2 0
7(300,400)sca2 1
我可以做的最好的是:
df2 $ cat = cut(df2 $ snp,seq(0,400,bin
include.lowest = TRUE)
df2
snp sca cat
1 1 sca1 [0,100]
2 2 sca1 [0,100]
3 10 sca1 [0,100]
4 100 sca1 [0,100]
5 1 sca2 [0,100]
6 2 sca2 [0,100]
7 14 sca2 [0,100]
8 16 sca2 [0,100]
9 399 sca2(300,400)
或者这个: p>
表(df2 $ cat,df2 $ sca)
sca1 sca2
[0,100] 4 4
(100,200] 0 0
(200,300)0 0
(300,400)0 1
但是最后一次尝试的问题是,(300,400)
不适用于 sca1
,因为它不存在。应该是 NA
或不显示。如何解决这个问题?
以下是使用 tidyverse
/ p>
库(dplyr)
库(tidyr)
库(purrr)
df%>%
left_join(nest(df2,snp,.key =snp),by = c(y=sca))%>%
mutate b $ b cut = map(x,〜seq(0,...,by = 100)),
tbls = pmap(
.l = list(snp,cutting),
.f = function(xx,break){
z < - table(cut(xx $ snp,breaks))
data_frame(cut = names(z),count = z)
}
)
)%>%
select(y,tbls)%>%
unnest()
#y cut count
#1 sca1(0,100 ] 4
#2 sca1(100,200] 0
#3 sca1(200,300)0
#4 sca2(0,100)4
#5 sca2(100,200)0
#6 sca2(200,300)0
#7 sca2(300,400)1
I would like to compute something really simple, but I don't find the solution. I want to cut in bins certain numbers, but I want to save the bins.
bin.size = 100
df = data.frame(x =c(300,400),
y = c("sca1","sca2"))
cut(df$x, seq(0, 400, bin.size),
include.lowest = TRUE)
Gives me
[1] (200,300] (300,400]
Levels: [0,100] (100,200] (200,300] (300,400]
But what I want something like this:
bin y
1 (0,100] sca1
2 (100,200] sca1
3 (200,300] sca1
4 (0,100] sca2
5 (100,200] sca2
6 (200,300] sca2
7 (300,400] sca2
I want to do this because I want to calculate the number of values that enter in bins of 100. For example:
df2 = data.frame(snp = c(1,2,10,100,1,2,14,16,399),
sca = c("sca1","sca1","sca1","sca1","sca2","sca2","sca2","sca2","sca2"))
df2
snp sca
1 1 sca1
2 2 sca1
3 10 sca1
4 100 sca1
5 1 sca2
6 2 sca2
7 14 sca2
8 16 sca2
9 399 sca2
snp could be the the position in a vector sca1.
The end goal is to obtain something like this:
bin y num
1 (0,100] sca1 4
2 (100,200] sca1 0
3 (200,300] sca1 0
4 (0,100] sca2 4
5 (100,200] sca2 0
6 (200,300] sca2 0
7 (300,400] sca2 1
The best I can do is this:
df2$cat = cut(df2$snp, seq(0, 400, bin.size),
include.lowest = TRUE)
df2
snp sca cat
1 1 sca1 [0,100]
2 2 sca1 [0,100]
3 10 sca1 [0,100]
4 100 sca1 [0,100]
5 1 sca2 [0,100]
6 2 sca2 [0,100]
7 14 sca2 [0,100]
8 16 sca2 [0,100]
9 399 sca2 (300,400]
Or this:
table(df2$cat,df2$sca)
sca1 sca2
[0,100] 4 4
(100,200] 0 0
(200,300] 0 0
(300,400] 0 1
But the problem with this last attempt is that the category (300,400]
doesn't make sense for sca1
because it doesn't exist. It should be NA
or not appearing. How to solve this?
Here's one way using a few packages from the tidyverse
:
library(dplyr)
library(tidyr)
library(purrr)
df %>%
left_join(nest(df2, snp, .key = "snp"), by = c("y" = "sca")) %>%
mutate(
cuts = map(x, ~ seq(0, ., by = 100)),
tbls = pmap(
.l = list(snp, cuts),
.f = function(xx, breaks) {
z <- table(cut(xx$snp, breaks))
data_frame(cut = names(z), count = z)
}
)
) %>%
select(y, tbls) %>%
unnest()
# y cut count
# 1 sca1 (0,100] 4
# 2 sca1 (100,200] 0
# 3 sca1 (200,300] 0
# 4 sca2 (0,100] 4
# 5 sca2 (100,200] 0
# 6 sca2 (200,300] 0
# 7 sca2 (300,400] 1
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