Infragistics XamDataGrid具有可变列数 [英] Infragistics XamDataGrid with variable number of columns

问题描述

我需要能够支持一个XamDataGrid，它在设计时不会有一组数量的列。例如，应用程序将运行，从服务器获取一些数据并创建一些对象。根据服务器的响应，每次运行应用程序时，我可能会有不同的对象数量。

这是我的意思的一个例子。让我说我打电话给一些服务，并得到一个xml响应与一些信息。我反序列化响应到一些对象，每次调用都可能会有所不同。

让每个对象有两个属性Label和Value。我希望网格显示具有与值值相匹配的标签的列。所以如果我有两个对象obj1和obj2，看起来像这样：

  obj1.Label =Parts
 obj1.Value =17
 
 obj2.Label =零件
 obj2.Value =12
  

我想要一个这样的网格，有两行：

零件

17

12

如果我将我的数据源绑定到网格，网格自动只使用对象的属性来创建列，因此我看到了标签和值的列：

标签值

零件17

零件12

我假设我不能通过xaml实现我想要的。有人有我正在寻找的例子吗？在运行时编程时，是否创建所有的列是由我自己决定的？

解决方案

  <网格> 
< DataGrid Name =dgTestAutoGenerateColumns =False> 
< DataGrid.Columns> 
< DataGridTemplateColumn> 
< DataGridTemplateColumn.HeaderTemplate> 
< DataTemplate> 
< StackPanel> 
< TextBlock Text ={Binding RelativeSource = {RelativeSource AncestorType = {x：Type DataGrid}}，Path = ItemsSource [0] .Label}/> 
< / StackPanel> 
< / DataTemplate> 
< /DataGridTemplateColumn.HeaderTemplate> 
< DataGridTemplateColumn.CellTemplate> 
< DataTemplate> 
< TextBlock Text ={Binding Path = Value}/> 
< / DataTemplate> 
< /DataGridTemplateColumn.CellTemplate> 
< / DataGridTemplateColumn> 
< /DataGrid.Columns> 
< / DataGrid> 
< / Grid> 
  

和代码：

  public partial class Window12：Window 
 {
 public Window12（）
 {
 InitializeComponent（）; 
 
列表< MyClass> l = new List< MyClass>（）; 
 
 l.Add（new MyClass 
 {
 Label =Parts，
 Value =17
}）; 
 
 l.Add（new MyClass 
 {
 Label =Parts，
 Value =12
}）; 
 
 dgTest.ItemsSource = l; 
} 
} 
 
 public class MyClass 
 {
 public string Label {get;组; } 
 public string Value {get;组; } 
} 
  

I need to be able to support a XamDataGrid which at design time will not have a set number of columns. For example, the app will run, get some data from the server and create some objects. Depending on the response from the server, I may have a different number of objects each time I run the app.

Here is an example of what I mean. Lets say I make a call to some service and get back an xml response with some info. I deserialize that response into a number of objects, which can be different each time the call is made.

Lets say each object has two properties, Label and Value. I would like the grid to show columns with labels that match the value of Label with values from Value. So if I have a two objects, obj1 and obj2, that look like this:

obj1.Label = "Parts"
obj1.Value = "17"

obj2.Label = "Parts"
obj2.Value = "12"

I would like a grid that looks like this, with two rows:

Parts

17

12

If I bind my data source to the grid, the grid automatically just uses the object's properties to create the columns, so I see columns of Label and Value:

Label Value

Parts 17

Parts 12

I am assuming that I cannot achieve what I want just via xaml. Does anyone have an example of what I am looking for? Is it just up to me to create all of the columns during runtime programatically?

解决方案

 <Grid>
    <DataGrid Name="dgTest" AutoGenerateColumns="False">
        <DataGrid.Columns>
            <DataGridTemplateColumn>
                <DataGridTemplateColumn.HeaderTemplate>
                    <DataTemplate>
                        <StackPanel>
                            <TextBlock Text="{Binding RelativeSource={RelativeSource AncestorType={x:Type DataGrid}}, Path=ItemsSource[0].Label}" />
                        </StackPanel>
                    </DataTemplate>
                </DataGridTemplateColumn.HeaderTemplate>
                <DataGridTemplateColumn.CellTemplate>
                    <DataTemplate>
                        <TextBlock Text="{Binding Path=Value}"/>
                    </DataTemplate>
                </DataGridTemplateColumn.CellTemplate>
            </DataGridTemplateColumn>
        </DataGrid.Columns>
    </DataGrid>
</Grid>

and code:

public partial class Window12 : Window
{
    public Window12()
    {
        InitializeComponent();

        List<MyClass> l = new List<MyClass>();

        l.Add(new MyClass
        {
            Label = "Parts",
            Value = "17"
        });

        l.Add(new MyClass
        {
            Label = "Parts",
            Value = "12"
        });

        dgTest.ItemsSource = l;
    }
}

public class MyClass
{
    public string Label { get; set; }
    public string Value { get; set; }
}

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