pandas 比较下一行 [英] Pandas compare next row
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问题描述
我有一个这样的数据框
d={}
d['z']=['Q8','Q8','Q7','Q9','Q9']
d['t']=['10:30','10:31','10:38','10:40','10:41']
d['qty']=[20,20,9,12,12]
我想将第一行与第二行进行比较
I want compare first row with second row
- 的数量与下一行的数量一致AND
- 在下一行中更大,而
- 的z值与下一行相同
所需的值为
qty t z valid
0 20 2015-06-05 10:30:00 Q8 False
1 20 2015-06-05 10:31:00 Q8 True
2 9 2015-06-05 10:38:00 Q7 False
3 12 2015-06-05 10:40:00 Q9 False
4 12 2015-06-05 10:41:00 Q9 True
推荐答案
看起来你想使用 Series.shift
方法。
Looks like you want to use the Series.shift
method.
使用此方法,可以生成与原始列偏移的新列。像这样:
Using this method, you can generate new columns which are offset to the original columns. Like this:
df['qty_s'] = df['qty'].shift(-1)
df['t_s'] = df['t'].shift(-1)
df['z_s'] = df['z'].shift(-1)
现在可以比较这些:
df['is_something'] = (df['qty'] == df['qty_s']) & (df['t'] < df['t_s']) & (df['z'] == df['z_s'])
如何 Series.shift
可以将下一行与当前的值进行比较:
Here is a simplified example of how Series.shift
works to compare next row to the current:
df = pd.DataFrame({"temp_celcius":pd.np.random.choice(10, 10) + 20}, index=pd.date_range("2015-05-15", "2015-05-24"))
df
temp_celcius
2015-05-15 21
2015-05-16 28
2015-05-17 27
2015-05-18 21
2015-05-19 25
2015-05-20 28
2015-05-21 25
2015-05-22 22
2015-05-23 29
2015-05-24 25
df["temp_c_yesterday"] = df["temp_celcius"].shift(1)
df
temp_celcius temp_c_yesterday
2015-05-15 21 NaN
2015-05-16 28 21
2015-05-17 27 28
2015-05-18 21 27
2015-05-19 25 21
2015-05-20 28 25
2015-05-21 25 28
2015-05-22 22 25
2015-05-23 29 22
2015-05-24 25 29
df["warmer_than_yesterday"] = df["temp_celcius"] > df["temp_c_yesterday"]
temp_celcius temp_c_yesterday warmer_than_yesterday
2015-05-15 21 NaN False
2015-05-16 28 21 True
2015-05-17 27 28 False
2015-05-18 21 27 False
2015-05-19 25 21 True
2015-05-20 28 25 True
2015-05-21 25 28 False
2015-05-22 22 25 False
2015-05-23 29 22 True
2015-05-24 25 29 False
如果我误解您的查询,请发表评论,我会更新我的答案。
If I misunderstood your query, please post a comment and I'll update my answer.
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