pandas 比较下一行 [英] Pandas compare next row

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问题描述

我有一个这样的数据框

d={}
d['z']=['Q8','Q8','Q7','Q9','Q9']
d['t']=['10:30','10:31','10:38','10:40','10:41']
d['qty']=[20,20,9,12,12]

我想将第一行与第二行进行比较

I want compare first row with second row


  1. 的数量与下一行的数量一致AND

  2. 在下一行中更大,而

  3. 的z值与下一行相同

所需的值为

   qty                   t   z  valid
0   20 2015-06-05 10:30:00  Q8  False
1   20 2015-06-05 10:31:00  Q8   True
2    9 2015-06-05 10:38:00  Q7  False
3   12 2015-06-05 10:40:00  Q9  False
4   12 2015-06-05 10:41:00  Q9   True


推荐答案

看起来你想使用 Series.shift 方法。

Looks like you want to use the Series.shift method.

使用此方法,可以生成与原始列偏移的新列。像这样:

Using this method, you can generate new columns which are offset to the original columns. Like this:

df['qty_s'] = df['qty'].shift(-1)
df['t_s'] = df['t'].shift(-1)
df['z_s'] = df['z'].shift(-1)

现在可以比较这些:

df['is_something'] = (df['qty'] == df['qty_s']) & (df['t'] < df['t_s']) & (df['z'] == df['z_s'])

如何 Series.shift 可以将下一行与当前的值进行比较:

Here is a simplified example of how Series.shift works to compare next row to the current:

df = pd.DataFrame({"temp_celcius":pd.np.random.choice(10, 10) + 20}, index=pd.date_range("2015-05-15", "2015-05-24")) 
df
            temp_celcius

2015-05-15            21
2015-05-16            28
2015-05-17            27
2015-05-18            21
2015-05-19            25
2015-05-20            28
2015-05-21            25
2015-05-22            22
2015-05-23            29
2015-05-24            25

df["temp_c_yesterday"] = df["temp_celcius"].shift(1)
df
            temp_celcius  temp_c_yesterday
2015-05-15            21               NaN
2015-05-16            28                21
2015-05-17            27                28
2015-05-18            21                27
2015-05-19            25                21
2015-05-20            28                25
2015-05-21            25                28
2015-05-22            22                25
2015-05-23            29                22
2015-05-24            25                29

df["warmer_than_yesterday"] = df["temp_celcius"] > df["temp_c_yesterday"]
            temp_celcius  temp_c_yesterday warmer_than_yesterday
2015-05-15            21               NaN                 False
2015-05-16            28                21                  True
2015-05-17            27                28                 False
2015-05-18            21                27                 False
2015-05-19            25                21                  True
2015-05-20            28                25                  True
2015-05-21            25                28                 False
2015-05-22            22                25                 False
2015-05-23            29                22                  True
2015-05-24            25                29                 False

如果我误解您的查询,请发表评论,我会更新我的答案。

If I misunderstood your query, please post a comment and I'll update my answer.

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