如何为R中的tableGrob定制特定的列? [英] How do I customize particular columns for a tableGrob in R?
问题描述
我正在寻找在我的tableGrob中定制特定的列,对于这个可重复的例子,我选择了查看自定义的对齐方式。假设您有以下数据框:
df < data.frame(Order = c(1:3),Name = c(Adam,Ben,Charlie),Score = c(4,8,9))
并且您想使用包 gridExtra
来显示表格:
dfGrob< - tableGrob(df,rows = NULL)
grid.arrange(dfGrob)
您可以通过调整用于构建grob的主题来调整列的对齐方式,例如:
tt1 < - ttheme_default(core = list(fg_params = list(hjust = 0,x = 0.05)),
colhead = list(fg_params =列表(hjust = 0,x = 0.1))
dfGrob< - tableGrob(df,rows = NULL,theme = tt1)
grid.arrange(dfGrob)
但是,这会调整所有列的对齐。说我只想左右秩序栏,让其他人放在他们中心的理由位置,我该如何做呢?
我已经尝试过:
tt1< - ttheme_default core = list(fg_params = list(hjust = c(0,0.5,0.5),x = c(0.15,0.5,0.5))),
/ pre>
colhead = list(fg_params = list(hjust = 1,x = 0.95)))
dfGrob< - tableGrob(df,rows = NULL,theme = tt1)
grid.arrange(dfGrob)
但这似乎是按行自定义的。如何调整此代码以按列自定义?
解决方案它有点fiddly,但您可以指定所有元素的参数,
库(网格)
库(gridExtra)
df< - data.frame(Order = c(1:3)
Name = c(Adam,Ben,Charlie),
Score = c(4,8,9))
hj< - matrix c(0,0.5,1),ncol = 3,nrow = nrow(df),byrow = TRUE)
x <矩阵(c(0,0.5,1)),ncol = 3,nrow = df),byrow = TRUE)
tt1 <-ttheme_default(core = list(fg_params = list(hjust = as.vector(hj),
x = as.vector(x)) ),
colhead = list(fg_params = list(hjust = 1,x = 0.95))
dfGrob< - tableGrob(df,rows = NULL,theme = tt1)
grid.newpage()
grid.draw(dfGrob)
I'm looking to customise particular columns in my tableGrob, for this reproducible example I have chosen to look at customising justification.
Say you have the following dataframe:
df <- data.frame(Order = c(1:3), Name = c("Adam", "Ben", "Charlie"), Score = c(4, 8, 9))
And you want to use the package
gridExtra
to present the table:dfGrob <- tableGrob(df, rows = NULL) grid.arrange(dfGrob)
You can adjust the alignment of the columns by adjusting the theme used to build the grob, for example:
tt1 <- ttheme_default(core=list(fg_params=list(hjust= 0, x=0.05)), colhead=list(fg_params=list(hjust=0, x=0.1))) dfGrob <- tableGrob(df, rows = NULL, theme = tt1) grid.arrange(dfGrob)
However, this adjusts the justification for all columns. Say I just want to left justify the Order Column, and leave the others in their central justification position, how would I do that?
I have experimented with:
tt1 <- ttheme_default(core=list(fg_params=list(hjust= c(0, 0.5, 0.5), x=c(0.15, 0.5, 0.5))), colhead=list(fg_params=list(hjust=1, x=0.95))) dfGrob <- tableGrob(df, rows = NULL, theme = tt1) grid.arrange(dfGrob)
But this just seems to customise by row. How do I adjust this code to customise by column instead?
解决方案it's a bit fiddly but you can specify the parameters for all elements,
library(grid) library(gridExtra) df <- data.frame(Order = c(1:3), Name = c("Adam", "Ben", "Charlie"), Score = c(4, 8, 9)) hj <- matrix(c(0, 0.5, 1), ncol=3, nrow=nrow(df), byrow=TRUE) x <- matrix(c(0, 0.5, 1), ncol=3, nrow=nrow(df), byrow=TRUE) tt1 <- ttheme_default(core=list(fg_params=list(hjust = as.vector(hj), x = as.vector(x))), colhead=list(fg_params=list(hjust=1, x=0.95))) dfGrob <- tableGrob(df, rows = NULL, theme = tt1) grid.newpage() grid.draw(dfGrob)
The recycling logic defaults to column wise, because most often a table has rows of alternating colours. It should be possible to special-case the horizontal justification parameters to make this a bit more user-friendly. Feel free to submit a PR.
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