创建一个自定义的DataGrid的ItemsSource [英] Create a custom DataGrid's ItemsSource

问题描述

我正在使用DataGrids，但我正在努力绑定我的数据，因为列数根据显示的信息而有所不同。

I am working with DataGrids but I am struggling to binding my data since the number of columns varies depending of the info that has to be showed.

所以，我试图做的是创建和对象，它包含我需要的所有列和行，并将该对象绑定到 ItemsSource 属性。因为我已经在WindowsForms中使用DataGridViews，所以我记住这样的一个例子：

So, what I have tried to do is to create and object which contains all the columns and rows that I need at some point and binding this object to the ItemsSource property. Since I have worked with DataGridViews in WindowsForms I have in mind something like this:

DataTable myTable = new DataTable();

DataColumn col01 = new DataColumn("col 01");
myTable.Columns.Add(col01);
DataColumn col02 = new DataColumn("col 02");
myTable.Columns.Add(col02);

DataRow row = myTable.NewRow();
row[0] = "data01";
row[1] = "data02";
myTable.Rows.Add(row);

row = myTable.NewRow();
row[0] = "data01";
row[1] = "data02";
myTable.Rows.Add(row);

但是，由于我需要，我无法找到一种在WPF中做同样的事情的方法一些列为DataGridComboBoxColumns为例。

But I haven't been able to find a way to do the same thing in WPF since I need some columns to be DataGridComboBoxColumns for example.

其实我在这个网站上看过很多帖子，但都没有帮助我。我真的迷路了。

Actually I have read many post about it in this site, but none of them helped to me. I am really lost.

有没有人可以帮助我？我只需要创建一个可能包含DataGridTextColumns或DataGridComboBoxColumns的表，以便将此最终对象绑定到DataGrid的ItemsSource属性。

Could anyone help me? I just need to be able to create a table which may contain DataGridTextColumns or `DataGridComboBoxColumns, etc, In order to bind this final object to the DataGrid's ItemsSource property.

希望有人可以帮助我。

推荐答案

好的，让我尝试一个类似于你的需求的例子

Okay, let me try to take an example which is similar to your needs

我们假设我们使用这个类：

Let's assume we use this class:

public class MyObject
{
   public int MyID;
   public string MyString;
   public ICommand MyCommand;
}

我们愿意显示一个 DataGrid 列出ID，并将属性 MyString 作为内容作为第二列 Button ，当被点击时，启动在新窗口中打开的 ICommand MyCommand 。无论你想要什么。

And we are willing to display a DataGrid listing the ID, and having as a second column a Button, with the property MyString as content, which, when clicked, launches the ICommand MyCommand which opens in a new window whatever you want.

这是你在View方面应该有的：

Here is what you should have on the View side:

    <DataGrid ItemsSource="{Binding MyList}" AutoGenerateColumns="False">
        <DataGrid.Columns>
            <DataGridTextColumn Header="ID" Binding="{Binding MyID}" />
            <DataGridTemplateColumn Header="Buttons">
                <DataGridTemplateColumn.CellTemplate>
                    <DataTemplate>
                        <Button Content="{Binding MyString}" Command="{Binding MyCommand}" />
                    </DataTemplate>
                </DataGridTemplateColumn.CellTemplate>
            </DataGridTemplateColumn>
        </DataGrid.Columns>
    </DataGrid>

这将显示一个 DataGrid IEnumerable< MyObject> 中的内容命名为MyList，并显示了之前定义的两列。

This will show a DataGrid taking all the content in an IEnumerable<MyObject> named 'MyList', and shows two columns as defined before.

现在如果你需要定义命令。
首先，我建议您阅读此MVVM介绍链接并采取 RelayCommand 类（这是我们将要用于您的问题）

Now if you need to define the command. First, I recommend you read this introductory link to MVVM and take the RelayCommand class (that's what we're gonna use for your problem)

所以，在您的 ViewModel ，定义 MyList 的那个，这里是如何定义一些有用的对象： p>

So, in your ViewModel, the one which defines the MyList, here is how you should define some of the useful objects:

public ObservableCollection<MyObject> MyList { get; set; }

// blah blah blah

public void InitializeMyList()
{
  MyList = new ObservableCollection<MyObject>();
  for (int i = 0; i < 5; i++)
  {
    MyList.Add(InitializeMyObject(i));
  }
}

public MyObject InitializeMyObject(int i)
{
  MyObject theObject = new MyObject();
  theObject.MyID = i;
  theObject.MyString = "The object " + i;
  theObject.MyCommand = new RelayCommand(param =< this.ShowWindow(i));
  return theObject
}

private void ShowWindow(int i)
{
  // Just as an exammple, here I just show a MessageBox
  MessageBox.Show("You clicked on object " + i + "!!!");
}

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