如何使数据表枚举? [英] How can I make DataTable enumerable?

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本文介绍了如何使数据表枚举?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我不能在DataTable上使用AsEnumerable(),我使用C#3,但我只是定位2.0框架(LINQ功能由 LINQBridge )。有没有办法使DataTable枚举,而不使用Select()?

  bool isExisting =(bdsAttachments.DataSource as DataTable)。 Select()。Any(xxx =>(string)dr [filename] == filename); 

更新:



使它看起来像这样:

  bool isExisting =(bdsAttachments.DataSource as DataTable).AsEnumerable()。Any(xxx => ;(string)dr [filename] == filename); 

我正在看到DataTable的Select方法返回一个副本,我在想只需使用AsEnumerable,问题是我只是针对2.0框架,System.Data.DataSetExtensions不可用



BTW,我尝试过: http://cs.rthand.com/blogs/blog_with_righthand/archive/2006/ 01/15 / 284.aspx ,但有编译错误。

解决方案

  public static IEnumerable< DataRow> EnumerateRows(这个DataTable表)
{
foreach(table.Rows中的var row)
{
yield return row;
}
}

允许您拨打:

  bool isExisting =(bdsAttachments.DataSource as DataTable).EnumerateRows()。any(dr =>(string)dr [filename] ==文件名); 


I cannot use AsEnumerable() on DataTable, I'm using C# 3 but I'm just targeting 2.0 framework (LINQ capability is courtesy of LINQBridge). Is there any way I can make DataTable enumerable without using Select() ?

bool isExisting = (bdsAttachments.DataSource as DataTable).Select().Any(xxx => (string)dr["filename"] == filename);

Update:

I wanted it to make it look like this:

bool isExisting = (bdsAttachments.DataSource as DataTable).AsEnumerable().Any(xxx => (string)dr["filename"] == filename);

I'm getting an inkling that the Select method of DataTable returns a copy, I'm thinking to just use AsEnumerable, the problem is I'm just targeting 2.0 framework, System.Data.DataSetExtensions is not available

BTW, i tried this: http://cs.rthand.com/blogs/blog_with_righthand/archive/2006/01/15/284.aspx, but has compilation errors.

解决方案

    public static IEnumerable<DataRow> EnumerateRows(this DataTable table)
    {
        foreach (var row in table.Rows)
        {
            yield return row;
        }
    }

Allows you to call:

bool isExisting = (bdsAttachments.DataSource as DataTable).EnumerateRows().Any(dr => (string)dr["filename"] == filename);

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