为什么Date.parse会给出不正确的结果? [英] Why does Date.parse give incorrect results?

查看:124
本文介绍了为什么Date.parse会给出不正确的结果?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

new Date(Date.parse("Jul 8, 2005"));



输出:



Fri Jul 08 2005 00:00:00 GMT-0700(PST)

Output:

Fri Jul 08 2005 00:00:00 GMT-0700 (PST)

new Date(Date.parse("2005-07-08"));



输出:



2005年7月7日17:00:00 GMT-0700(PST)

Output:

Thu Jul 07 2005 17:00:00 GMT-0700 (PST)

为什么第二个解析不正确?

Why is the second parse incorrect?

推荐答案

直到第5版规格出来, Date.parse 方法完全依赖于实现新的日期(字符串)相当于 Date.parse(string) ,除了后者返回一个数字而不是 Date )。在第5版规范中,添加了要求,以支持简化(稍微不正确) ISO-8601 ,但除此之外,对于 Date.parse 否 $ c> / new Date(string)应该接受,除了他们不得不接受任何 Date#toString output不用说这是什么)。

Until the 5th edition spec came out, the Date.parse method was completely implementation dependent (new Date(string) is equivalent to Date.parse(string) except the latter returns a number rather than a Date). In the 5th edition spec the requirement was added to support a simplified (and slightly incorrect) ISO-8601, but other than that, there was no requirement for what Date.parse / new Date(string) should accept other than that they had to accept whatever Date#toString output (without saying what that was).

我建议您手动解析日期字符串,并使用 Date构造函数与年,月和日参数以避免歧义:

I would recommend you to parse your date string manually, and use the Date constructor with the year, month and day arguments to avoid ambiguity:

// parse a date in yyyy-mm-dd format
function parseDate(input) {
  var parts = input.split('-');
  // new Date(year, month [, day [, hours[, minutes[, seconds[, ms]]]]])
  return new Date(parts[0], parts[1]-1, parts[2]); // Note: months are 0-based
}

这篇关于为什么Date.parse会给出不正确的结果?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

查看全文
登录 关闭
扫码关注1秒登录
发送“验证码”获取 | 15天全站免登陆