计算一周的星期数一周数 [英] Calculating days of week given a week number

问题描述

给定一个周数，例如 date -u +％W ，您如何计算从星期一开始的那一周的天数？

示例rfc -3339第40周输出：

  2008-10-06 
 2008-10-07 
 2008 -10-08 
 2008-10-09 
 2008-10-10 
 2008-10-11 
 2008-10-12 
  

解决方案

PHP

  $ week_number = 40; 
 $ year = 2008; 
（$ day = 1; $ day< = 7; $ day ++）
 {
回显日期（'m / d / Y'，strtotime（$ year。W week_number。$ day））。\\\
; 
} 
  

---

以下帖子是因为我是个白痴没有正确地阅读这个问题，但是从星期一开始，一周内就会收到日期，而不是周数。

在PHP中改编自这篇文章在 PHP日期手册页：

  function week_from_monday（$ date）{
 //假设$ date的格式为DD-MM-YYYY 
列表（$ day，$ month，$ year ）= explode（ - ，$ _REQUEST [date]）; 
 
 //获取给定日期的工作日
 $ wkday = date（'l'，mktime（'0'，'0'，'0'，$ month，$ day， $ year））; 
 
 switch（$ wkday）{
 case'Monday'：$ numDaysToMon = 0;打破; 
 case'Tuesday'：$ numDaysToMon = 1;打破; 
 case'Wednesday'：$ numDaysToMon = 2;打破; 
 case'Thursday'：$ numDaysToMon = 3;打破; 
 case'Friday'：$ numDaysToMon = 4;打破; 
 case'Saturday'：$ numDaysToMon = 5;打破; 
 case'Sunday'：$ numDaysToMon = 6;打破; 
} 
 
 //周一星期的时间戳
 $ monday = mktime（'0'，'0'，'0'，$ month，$ day- $ numDaysToMon，$ year）; 
 
 $ seconds_in_a_day = 86400; 
 
 //从星期一（含）获取7天的日期
（$ i = 0; $ i< 7; $ i ++）
 {
 $ [$ i] = date（'Ym-d'，$ monday +（$ seconds_in_a_day * $ i））; 
} 
 
返回$日期; 
} 
  

的输出week_from_monday（'07 -10-2008 '）给出：

  Array 
（
 [0] => ; 2008-10-06 
 [1] => 2008-10-07 
 [2] => 2008-10-08 
 [3] => 2008-10- 09 
 [4] => 2008-10-10 
 [5] => 2008-10-11 
 [6] => 2008-10-12 
 ）
  

Given a week number, e.g. date -u +%W, how do you calculate the days in that week starting from Monday?

Example rfc-3339 output for week 40:

2008-10-06
2008-10-07
2008-10-08
2008-10-09
2008-10-10
2008-10-11
2008-10-12

解决方案

PHP

$week_number = 40;
$year = 2008;
for($day=1; $day<=7; $day++)
{
    echo date('m/d/Y', strtotime($year."W".$week_number.$day))."\n";
}

---

Below post was because I was an idiot who didn't read the question properly, but will get the dates in a week starting from Monday, given the date, not the week number..

In PHP, adapted from this post on the PHP date manual page:

function week_from_monday($date) {
    // Assuming $date is in format DD-MM-YYYY
    list($day, $month, $year) = explode("-", $_REQUEST["date"]);

    // Get the weekday of the given date
    $wkday = date('l',mktime('0','0','0', $month, $day, $year));

    switch($wkday) {
        case 'Monday': $numDaysToMon = 0; break;
        case 'Tuesday': $numDaysToMon = 1; break;
        case 'Wednesday': $numDaysToMon = 2; break;
        case 'Thursday': $numDaysToMon = 3; break;
        case 'Friday': $numDaysToMon = 4; break;
        case 'Saturday': $numDaysToMon = 5; break;
        case 'Sunday': $numDaysToMon = 6; break;   
    }

    // Timestamp of the monday for that week
    $monday = mktime('0','0','0', $month, $day-$numDaysToMon, $year);

    $seconds_in_a_day = 86400;

    // Get date for 7 days from Monday (inclusive)
    for($i=0; $i<7; $i++)
    {
        $dates[$i] = date('Y-m-d',$monday+($seconds_in_a_day*$i));
    }

    return $dates;
}

Output from week_from_monday('07-10-2008') gives:

Array
(
    [0] => 2008-10-06
    [1] => 2008-10-07
    [2] => 2008-10-08
    [3] => 2008-10-09
    [4] => 2008-10-10
    [5] => 2008-10-11
    [6] => 2008-10-12
)

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