优雅的方式来获取两个日期之间的月份数? [英] Elegant way to get the count of months between two dates?

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问题描述

假设我在变量中有两个日期,如

  $ date1 =2009-09-01; 
$ date2 =2010-05-01;

我需要得到 $ date2 $ date1 $ date2> = $ date1 )。即我需要得到 8



有没有办法通过使用 date 函数,或者我必须爆炸我的字符串并做一些计算?



感谢很多

解决方案

对于PHP> = 5.3

  $ d1 = new DateTime(2009-09-01); 
$ d2 = new DateTime(2010-05-01);

var_dump($ d1-> diff($ d2) - > m); // int(4)
var_dump($ d1-> diff($ d2) - > m +($ d1-> diff($ d2) - > y * 12)); // int(8)

DateTime :: diff返回一个 DateInterval 对象



如果您不运行PHP 5.3或更高版本,我想你必须使用unix时间戳:

  $ d1 =2009-09-01; 
$ d2 =2010-05-01;

echo(int)abs((strtotime($ d1) - strtotime($ d2))/(60 * 60 * 24 * 30)); // 8

但它不是很精确(每个月并不总是30天) / p>

最后一件事:如果这些日期来自您的数据库,那么使用您的DBMS来完成此工作,而不是PHP。



编辑:如果您无法使用DateTime :: diff或RDBMS,则此代码应更精确:

 code> $ d1 = strtotime(2009-09-01); 
$ d2 = strtotime(2010-05-01);
$ min_date = min($ d1,$ d2);
$ max_date = max($ d1,$ d2);
$ i = 0;

while(($ min_date = strtotime(+ 1 MONTH,$ min_date))< = $ max_date){
$ i ++;
}
echo $ i; // 8


Let's assume i have two dates in variables, like

$date1 = "2009-09-01";
$date2 = "2010-05-01";

I need to get the count of months between $date2 and $date1($date2 >= $date1). I.e. i need to get 8.

Is there a way to get it by using date function, or i have to explode my strings and do some calculations?

Thanks much

解决方案

For PHP >= 5.3

$d1 = new DateTime("2009-09-01");
$d2 = new DateTime("2010-05-01");

var_dump($d1->diff($d2)->m); // int(4)
var_dump($d1->diff($d2)->m + ($d1->diff($d2)->y*12)); // int(8)

DateTime::diff returns a DateInterval object

If you don't run with PHP 5.3 or higher, I guess you'll have to use unix timestamps :

$d1 = "2009-09-01";
$d2 = "2010-05-01";

echo (int)abs((strtotime($d1) - strtotime($d2))/(60*60*24*30)); // 8

But it's not very precise (there isn't always 30 days per month).

Last thing : if those dates come from your database, then use your DBMS to do this job, not PHP.

Edit: This code should be more precise if you can't use DateTime::diff or your RDBMS :

$d1 = strtotime("2009-09-01");
$d2 = strtotime("2010-05-01");
$min_date = min($d1, $d2);
$max_date = max($d1, $d2);
$i = 0;

while (($min_date = strtotime("+1 MONTH", $min_date)) <= $max_date) {
    $i++;
}
echo $i; // 8

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