PHP日期格式/日期(1365004652303-0500)/ [英] PHP date format /Date(1365004652303-0500)/

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本文介绍了PHP日期格式/日期(1365004652303-0500)/的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我正在从我从哪里获取日期的API中调用 / Date(1365004652303-0500)/ ,我不明白这是什么格式。我们称之为日期格式?我不知道谷歌是如何使用这种格式的。

I am calling an API from where I am getting date /Date(1365004652303-0500)/, I don't understand what format this is. What we call this date format? I was not sure what to google for such type of format.

任何人都可以帮助我了解这个日期在 Ymd H:i:s 格式?

Can anyone help me out in getting this date in Y-m-d H:i:s format?

我正在调用的API是在.NET服务器上。当我使用PHP的 file_get_contents json_decode 命名它时,它给出了以下创建日期的日期格式: / Date(1365004652303-0500)/

The API I am calling is on .NET server. And when I call it using PHP's file_get_contents and json_decodeing it gives me following Date format for created date: /Date(1365004652303-0500)/

推荐答案

首先你需要了解格式你有

First you need to understand the format you have

/Date(1365004652303-0500)/

然后你有


  • 时间戳(U)= 1365004652

  • 微秒(u)= 303

  • 与格林尼治时间(GMT)的差异(O)= -0500

构建格式

$date = '/Date(1365004652303-0500)/';
preg_match('/(\d{10})(\d{3})([\+\-]\d{4})/', $date, $matches);
$dt = DateTime::createFromFormat("U.u.O",vsprintf('%2$s.%3$s.%4$s', $matches));
echo $dt->format('r');

输出

Wed, 03 Apr 2013 15:57:32 -0500
                            ^
                            |= Can you see the GMT ? 







interface DateFormatParser
{
    /**
     * @param $string
     *
     * @return DateTime
     */
    public function parse($string);

}

abstract class PregDateParser implements DateFormatParser
{
    protected $pattern, $format, $mask;

    public function parse($string) {
        $string = (string)$string;

        $pattern = $this->pattern;
        $format  = $this->format;
        $mask    = $this->mask;

        $r = preg_match($pattern, $string, $matches);
        if (!$r) {
            throw new UnexpectedValueException('Preg Regex Pattern failed.');
        }
        $buffer = vsprintf($mask, $matches);
        $result = DateTime::createFromFormat($format, $buffer);
        if (!$result) {
            throw new UnexpectedValueException(sprintf('Failed To Create from Format "%s" for "%s".', $format, $buffer));
        }
        return $result;
    }
}

class JsonTimestampWithOffsetParser extends PregDateParser
{
    protected $pattern = '/^\/Date\((\d{10})(\d{3})([+-]\d{4})\)\/$/';
    protected $format  = 'U.u.O';
    protected $mask    = '%2$s.%3$s.%4$s';
}

$date   = '/Date(1365004652303-0500)/';
$parser = new JsonTimestampWithOffsetParser;
$dt     = $parser->parse($date);

echo $dt->format('r');

这篇关于PHP日期格式/日期(1365004652303-0500)/的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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