PHP日期格式/日期(1365004652303-0500)/ [英] PHP date format /Date(1365004652303-0500)/
问题描述
我正在从我从哪里获取日期的API中调用 / Date(1365004652303-0500)/
,我不明白这是什么格式。我们称之为日期格式?我不知道谷歌是如何使用这种格式的。
I am calling an API from where I am getting date /Date(1365004652303-0500)/
, I don't understand what format this is. What we call this date format? I was not sure what to google for such type of format.
任何人都可以帮助我了解这个日期在 Ymd H:i:s
格式?
Can anyone help me out in getting this date in Y-m-d H:i:s
format?
我正在调用的API是在.NET服务器上。当我使用PHP的 file_get_contents
和 json_decode
命名它时,它给出了以下创建日期的日期格式: / Date(1365004652303-0500)/
The API I am calling is on .NET server. And when I call it using PHP's file_get_contents
and json_decode
ing it gives me following Date format for created date: /Date(1365004652303-0500)/
推荐答案
首先你需要了解格式你有
First you need to understand the format you have
/Date(1365004652303-0500)/
然后你有
- 时间戳(U)= 1365004652
- 微秒(u)= 303
- 与格林尼治时间(GMT)的差异(O)= -0500
构建格式
$date = '/Date(1365004652303-0500)/';
preg_match('/(\d{10})(\d{3})([\+\-]\d{4})/', $date, $matches);
$dt = DateTime::createFromFormat("U.u.O",vsprintf('%2$s.%3$s.%4$s', $matches));
echo $dt->format('r');
输出
Wed, 03 Apr 2013 15:57:32 -0500
^
|= Can you see the GMT ?
interface DateFormatParser
{
/**
* @param $string
*
* @return DateTime
*/
public function parse($string);
}
abstract class PregDateParser implements DateFormatParser
{
protected $pattern, $format, $mask;
public function parse($string) {
$string = (string)$string;
$pattern = $this->pattern;
$format = $this->format;
$mask = $this->mask;
$r = preg_match($pattern, $string, $matches);
if (!$r) {
throw new UnexpectedValueException('Preg Regex Pattern failed.');
}
$buffer = vsprintf($mask, $matches);
$result = DateTime::createFromFormat($format, $buffer);
if (!$result) {
throw new UnexpectedValueException(sprintf('Failed To Create from Format "%s" for "%s".', $format, $buffer));
}
return $result;
}
}
class JsonTimestampWithOffsetParser extends PregDateParser
{
protected $pattern = '/^\/Date\((\d{10})(\d{3})([+-]\d{4})\)\/$/';
protected $format = 'U.u.O';
protected $mask = '%2$s.%3$s.%4$s';
}
$date = '/Date(1365004652303-0500)/';
$parser = new JsonTimestampWithOffsetParser;
$dt = $parser->parse($date);
echo $dt->format('r');
这篇关于PHP日期格式/日期(1365004652303-0500)/的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!