从日期数组获取最近的日期 [英] Get most recent date from an array of dates

问题描述

我有数组的日期在

array(5) { 
    [0]=> string(19) "2012-06-11 08:30:49" 
    [1]=> string(19) "2012-06-07 08:03:54" 
    [2]=> string(19) "2012-05-26 23:04:04" 
    [3]=> string(19) "2012-05-27 08:30:00" 
    [4]=> string(19) "2012-06-08 08:30:55" 
}

并希望知道最近日期的 ：最接近今天的日期。

and would like to know the most recent date as in: the closest to today's date.

这样做？

推荐答案

执行循环，将值转换为日期，并将最近的值存储在var。

Do a loop, convert the values to date, and store the most recent, in a var.

$mostRecent= 0;
foreach($dates as $date){
  $curDate = strtotime($date);
  if ($curDate > $mostRecent) {
     $mostRecent = $curDate;
  }
}

类似的东西...你得到的想法
如果您想要今天最近的日期：

something like that... you get the idea If you want most recent BEFORE today :

$mostRecent= 0;
$now = time();
foreach($dates as $date){
  $curDate = strtotime($date);
  if ($curDate > $mostRecent && $curDate < $now) {
     $mostRecent = $curDate;
  }
}

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