php - 添加两个小时至今的变量 [英] php - add two hours to date variable
本文介绍了php - 添加两个小时至今的变量的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我从一个字符串中做出了这样的变量:(这是RFC 2822日期格式btw)
$ date = 2011-10-18T19:56:00 + 0200
I使用以下命令将该字符串转换为日期:
$ time = date_format(DateTime :: createFromFormat(Ymd\TH:i :sO,$ date),G:i)
现在,我想添加3分钟到该变量,但我不知道如何。
我以前在我的脚本中使用了以下命令,但是这适用于当前的日期/时间,所以我不知道如何使用它作为我的时间变量:
$ currenttime = date('G:i',strtotime('+ 2 hours'));
那么如何在$ time变量中添加三分钟?
$ b $ echo
echo $ idate =2013-09-25 09:29:44
$ effectiveDate = strtotime(+ 40 minutes,strtotime($ idate));
echo date(Y-m-d h:i:s,$ effectiveDate);
I want to add 3 minutes to a date/time variable I have, but I'm not sure how to do this. I made the variable from a string like this: (which is in the RFC 2822 date format btw)
$date = 2011-10-18T19:56:00+0200
I converted that string into date using this command:
$time = date_format(DateTime::createFromFormat("Y-m-d\TH:i:sO", $date), "G:i")
Now, I'd like to add 3 minutes to that variable, but I I'm not sure how. I've used the following command in my script before, but that applies to the current date/time, so I'm not sure how to use that for my time variable:
$currenttime = date('G:i', strtotime('+2 hours'));
So, how can I add three minutes to the $time variable?
解决方案
echo $idate="2013-09-25 09:29:44";
$effectiveDate = strtotime("+40 minutes", strtotime($idate));
echo date("Y-m-d h:i:s",$effectiveDate);
这篇关于php - 添加两个小时至今的变量的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!
查看全文