为什么这个操作与日期（2个日期之间的天数）返回此值？ [英] Why this operation with date (number of days between 2 dates) return this value?

问题描述

根据这个

According to this question, I wrote "my code" (without Math.abs, I don't need it) :

var oneDay = 24 * 60 * 60 * 1000; // hours*minutes*seconds*milliseconds
var firstDate = new Date("2011", "09", "28"); // 28 september 2011
var secondDate = new Date("2011", "09", "30"); // 30 september 2011

var notti = ((secondDate.getTime() - firstDate.getTime()) / (oneDay));
if (notti < 1)
    notti = 1;
else
    notti = Math.round(notti);

alert(notti);

并打印2（正确）。

现在，如果我这样做：

var oneDay = 24 * 60 * 60 * 1000; // hours*minutes*seconds*milliseconds
var firstDate = new Date("2011", "09", "28"); // 28 september 2011
var secondDate = new Date("2011", "10", "01"); // 01 october 2011

var notti = ((secondDate.getTime() - firstDate.getTime()) / (oneDay));
if (notti < 1)
    notti = 1;
else
    notti = Math.round(notti);

alert(notti);

它打印4.为什么4？应该是3 ...
你知道这个问题吗？

it print 4. Why 4? It should be 3... Do you know about this problem?

推荐答案

日期构造函数中的月份参数（和其他日期方法）从[0.11]不是[1..12]运行，所以：

The month argument in the date constructor (and other date methods) runs from [0.11] not [1..12] so:

new Date("2011", "09", "28"); // 28 september 2011

实际上是 Fri Oct 28 而不是9月。

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