CMD中的ISO周数 [英] ISO week number in CMD

问题描述

如何在Windows批处理文件中确定（ ISO 8601 ）周号？

How can I determine the (ISO 8601) week number in a Windows batch file?

不幸的是 WMIC PATH WIN32_LOCALTIME GET / FORMAT：LIST 只有 WeekInMonth ...

Unfortunately WMIC PATH WIN32_LOCALTIME GET /FORMAT:LIST only has WeekInMonth...

我发现一些非常< a> 复杂 解决方案。有没有更简单的方法？

I have found some very complex solutions. Is there no easier way?

推荐答案

这个工作可以到2100年3月6日：

This will work up to March 6th, 2100:

FOR /f %%a IN ('WMIC PATH WIN32_LOCALTIME GET /FORMAT:LIST') DO @(SET %%a>NUL)
SET /A a=(14-%Month%)/12,y=%Year%-a,IsoWeek=(%Day%+(153*(%Month%+12*a-3)+2)/5+365*y+y/4)/7-(365*%Year%+(%Year%+3)/4)/7+9

第一行将 WMIC 输出放入环境变量中。第二行使％IsoWeek％包含ISO周数。它将包含每年1月4日的1。

The first line puts the WMIC output into environment variables. The second line makes %IsoWeek% contain the ISO week number. It will contain 1 for January 4th of each year.

异常： 0 意味着它是上一个年（52或53），有时是53，实际上是明年的第1周。确定这些年度边界将进一步使计算复杂化。

Exception: 0 means it's the last week of the previous year (52 or 53) and sometimes it's 53 where it should actually be week 1 of the next year. Fixing these year boundaries would further complicate the calculations.

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