将8位整数转换成dd / mm / yyyy [英] Converting an 8-digit integer into dd/mm/yyyy

问题描述

所以我在PHP脚本中有这个功能，它应该把日期作为一个8位数的整数，如 01042012 并将其转换为 01/04/2012 显示。

So i have this function in my PHP script that is supposed to take the date as an 8-digit integer such as 01042012 and convert it to 01/04/2012 for displaying.

目前我正在尝试使用php的 date（）函数如下：

Currently i'm trying to use php's date() function as follows:

$int = 01042012;

$date = date("d/m/Y", $int);

而不是 $ date code> 01/04/2012 它显示为 13/01/1970 。

Instead of $date having the value 01/04/2012 it shows as 13/01/1970.

这是因为 date（）希望我传递给它的日期是在unix时间？如果是这样，可能还有一种更直接的方式来分割字符2和4之后的int，然后插入斜杠，然后重新组合？就像 explode（）一样，但是我没有字符可以分割。

Is this because date() wants the date i pass to it to be in unix time? If so, would there perhaps be a more direct way to split the int after characters 2 and 4 and just insert the slashes, then recombine it? Like what explode() does, but i have no character to split with.

推荐答案

一个简单的方法;

$int = 01042012;

$day = substr($int,0,2);
$month = substr($int,2,4);
$year = substr($int,4);

$date = $day.'/'.$month.'/'.$year;

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