一年如何计算耶稣受难日的日期？ [英] How can I calculate what date Good Friday falls on, given a year?

问题描述

有没有人有一个很好的算法来计算今年耶稣受难节在给定的年份作为一个输入？最好在C＃中。

解决方案

这是一篇伟大的文章，应该可以帮助您构建算法。

http://www.codeproject.com/KB/datetime/christianholidays。 aspx

根据这个例子，你应该可以写：

  DateTime goodFriday = EasterSunday（DateTime.Now.Year）.AddDays（-2）; 
  

完整示例：

  public static DateTime EasterSunday（int year）
 {
 int day = 0; 
 int month = 0; 
 
 int g =年％19; 
 int c = year / 100; 
 int h =（c  - （int）（c / 4） - （int）（（8 * c + 13）/ 25）+ 19 * g + 15）％30; $（$）$（$）$（$）$（$）$（$） g）/ 11））; 
 
 day = i  - （（年+（int）（年/ 4）+ i + 2  -  c +（int）（c / 4））％7）+ 28; 
 month = 3; 
 
 if（day> 31）
 {
 month ++; 
 day  -  = 31; 
} 
 
返回新的DateTime（年，月，日）; 
} 
  

Does anyone have a good algorithm to calculate what date Good Friday falls on given the year as an input? Preferably in C#.

解决方案

Here's a great article that should help you build your algorithm

http://www.codeproject.com/KB/datetime/christianholidays.aspx

Based on this example, you should be able to write:

DateTime goodFriday = EasterSunday(DateTime.Now.Year).AddDays(-2);

Full Example:

public static DateTime EasterSunday(int year)
{
    int day = 0;
    int month = 0;

    int g = year % 19;
    int c = year / 100;
    int h = (c - (int)(c / 4) - (int)((8 * c + 13) / 25) + 19 * g + 15) % 30;
    int i = h - (int)(h / 28) * (1 - (int)(h / 28) * (int)(29 / (h + 1)) * (int)((21 - g) / 11));

    day   = i - ((year + (int)(year / 4) + i + 2 - c + (int)(c / 4)) % 7) + 28;
    month = 3;

    if (day > 31)
    {
        month++;
        day -= 31;
    }

    return new DateTime(year, month, day);
}

这篇关于一年如何计算耶稣受难日的日期？的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！