ORA-01843不是有效的月份 - 比较日期 [英] ORA-01843 not a valid month- Comparing Dates
问题描述
当我们尝试从按日期筛选的表格中选择数据时,我遇到问题。例如:
I have a problem when try to select data from a table filtering by date. For example:
SELECT * FROM MYTABLE WHERE MYTABLE.DATEIN = '23 / 04/49';
SELECT * FROM MYTABLE WHERE MYTABLE.DATEIN = '23/04/49';
Oracle错误是:
The Oracle Error is:
Informe de error:
Error SQL: ORA-01843: mes no válido
01843. 00000 - "not a valid month"
*Cause:
*Action:
可能表的源数据已损坏,在这种情况下:我如何解决这个问题?
我可以将此日期更改为null吗?
Probably the source data of table is corrupted, in this case: How can i solve this problem? Can i change this dates for null?
此选择的结果,从nls_session_parameters中选择* ,是:
The results of this select, select * from nls_session_parameters; , is:
PARAMETER VALUE
------------------------------ ----------------------------------------
NLS_LANGUAGE SPANISH
NLS_TERRITORY SPAIN
NLS_CURRENCY ¿
NLS_ISO_CURRENCY SPAIN
NLS_NUMERIC_CHARACTERS ,.
NLS_CALENDAR GREGORIAN
NLS_DATE_FORMAT DD/MM/RR
NLS_DATE_LANGUAGE SPANISH
NLS_SORT SPANISH
NLS_TIME_FORMAT HH24:MI:SSXFF
NLS_TIMESTAMP_FORMAT DD/MM/RR HH24:MI:SSXFF
NLS_TIME_TZ_FORMAT HH24:MI:SSXFF TZR
NLS_TIMESTAMP_TZ_FORMAT DD/MM/RR HH24:MI:SSXFF TZR
NLS_DUAL_CURRENCY ¿
NLS_COMP BINARY
NLS_LENGTH_SEMANTICS BYTE
NLS_NCHAR_CONV_EXCP FALSE
谢谢!
推荐答案
你应使用to_date函数 http://www.techonthenet.com/oracle/functions/to_date.php
You should use the to_date function http://www.techonthenet.com/oracle/functions/to_date.php
SELECT * FROM MYTABLE WHERE MYTABLE.DATEIN = TO_DATE('23/04/49', 'DD/MM/YY');
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