PHP日期时间大于今天 [英] PHP date time greater than today

问题描述

请帮助我的代码错了。总是显示今天大于01/02/2016？在2016年大于2015年。

 <？php 
 $ date_now = date（m / d / Y）; 
 
 $ date = date_create（01/02/2016）; 
 $ date_convert = date_format（$ date，m / d / Y）; 
 
 if（$ date_now> $ date_convert）{
 echo'greater than'; 
} else {
 echo'Less than'; 
} 
  

PS：01/02/2016来自我的数据库

解决方案

您不是比较日期。您正在比较字符串。在'09/17/2015>'01/02/2016'的世界中，因为'09'>'01'，您需要将日期放在可比较的字符串格式中，或者比较可比较的DateTime对象。

 <？php 
 $ date_now = date（Ymd）; //此格式是字符串可比
 
 if（$ date_now>'2016-01-02'）{
 echo'greater than'; 
} else {
 echo'Less than'; 
} 
  

演示

或

  <？php 
 $ date_now = new DateTime（）; 
 $ date2 = new DateTime（01/02/2016）; 
 
 if（$ date_now> $ date2）{
 echo'greater than'; 
} else {
 echo'Less than'; 
} 
  

演示

please help whats wrong with my code. it always shows that today is greater than 01/02/2016 ? where in 2016 is greater than 2015.

<?php
 $date_now = date("m/d/Y");

$date=date_create("01/02/2016");
$date_convert = date_format($date,"m/d/Y");

if ($date_now > $date_convert) {
        echo 'greater than';
    }else{
        echo 'Less than';
    }

P.S : 01/02/2016 is coming from my database

解决方案

You are not comparing dates. You are comparing strings. In the world of string comparisons, '09/17/2015" > '01/02/2016' because '09' > '01'. You need to either put your date in a comparable string format or compare DateTime objects which are comparable.

<?php
 $date_now = date("Y-m-d"); // this format is string comparable

if ($date_now > '2016-01-02') {
        echo 'greater than';
    }else{
        echo 'Less than';
    }

Demo

Or

<?php
 $date_now = new DateTime();
 $date2    = new DateTime("01/02/2016");

if ($date_now > $date2) {
        echo 'greater than';
    }else{
        echo 'Less than';
    }

Demo

这篇关于PHP日期时间大于今天的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！